A faster way to compute the largest prime factor Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?Project Euler #3 - largest prime factorFaster way to determine largest prime factorx64 Assembly - checking for largest prime factorProject Euler #3 (Largest prime factor) in SwiftProject Euler 3: Getting the largest prime factor of a numberVery slow Project Euler Q3 (largest prime factor of a large number)Project Euler 3: Largest prime factorLargest prime factor of a given numberProject Euler 3 - Largest prime factorEuler problem 3: largest prime factor of the numberWork out largest prime factor of a number

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A faster way to compute the largest prime factor



Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?Project Euler #3 - largest prime factorFaster way to determine largest prime factorx64 Assembly - checking for largest prime factorProject Euler #3 (Largest prime factor) in SwiftProject Euler 3: Getting the largest prime factor of a numberVery slow Project Euler Q3 (largest prime factor of a large number)Project Euler 3: Largest prime factorLargest prime factor of a given numberProject Euler 3 - Largest prime factorEuler problem 3: largest prime factor of the numberWork out largest prime factor of a number



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1












$begingroup$


I am self-learning js and came across this problem(#3) from the Euler Project




The prime factors of 13195 are 5, 7, 13 and 29.



What is the largest prime factor of the number 600851475143 ?




Logic:



  • Have an array primes to store all the prime numbers less than number


  • Loop through the odd numbers only below number to check for primes using i



  • Check if i is divisible by any of the elements already in primes.



    • If yes, isPrime = false and break the for loop for j by j=primesLength

    • If not, isPrime = true



  • If isPrime == true then add i to the array primes and check if number%i == 0



    • If number%i == 0% update the value of factor as factor = i


  • Return factor after looping through all the numbers below number


My code:






function problem3(number)
let factor = 1;
let primes = [2]; //array to store prime numbers

for(let i=3; i<number; i=i+2) //Increment i by 2 to loop through only odd numbers
let isPrime = true;
let primesLength= primes.length;

for(let j=0; j< primesLength; j++)
if(i%primes[j]==0)
isPrime = false;
j=primesLength; //to break the for loop



if(isPrime == true)
primes.push(i);
if(number%i == 0)
factor = i;



return factor;


console.log(problem3(600851475143));





It is working perfectly for small numbers, but is quite very slow for 600851475143. What should I change in this code to make the computation faster?










share|improve this question









New contributor




Eagle is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$


















    1












    $begingroup$


    I am self-learning js and came across this problem(#3) from the Euler Project




    The prime factors of 13195 are 5, 7, 13 and 29.



    What is the largest prime factor of the number 600851475143 ?




    Logic:



    • Have an array primes to store all the prime numbers less than number


    • Loop through the odd numbers only below number to check for primes using i



    • Check if i is divisible by any of the elements already in primes.



      • If yes, isPrime = false and break the for loop for j by j=primesLength

      • If not, isPrime = true



    • If isPrime == true then add i to the array primes and check if number%i == 0



      • If number%i == 0% update the value of factor as factor = i


    • Return factor after looping through all the numbers below number


    My code:






    function problem3(number)
    let factor = 1;
    let primes = [2]; //array to store prime numbers

    for(let i=3; i<number; i=i+2) //Increment i by 2 to loop through only odd numbers
    let isPrime = true;
    let primesLength= primes.length;

    for(let j=0; j< primesLength; j++)
    if(i%primes[j]==0)
    isPrime = false;
    j=primesLength; //to break the for loop



    if(isPrime == true)
    primes.push(i);
    if(number%i == 0)
    factor = i;



    return factor;


    console.log(problem3(600851475143));





    It is working perfectly for small numbers, but is quite very slow for 600851475143. What should I change in this code to make the computation faster?










    share|improve this question









    New contributor




    Eagle is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$














      1












      1








      1





      $begingroup$


      I am self-learning js and came across this problem(#3) from the Euler Project




      The prime factors of 13195 are 5, 7, 13 and 29.



      What is the largest prime factor of the number 600851475143 ?




      Logic:



      • Have an array primes to store all the prime numbers less than number


      • Loop through the odd numbers only below number to check for primes using i



      • Check if i is divisible by any of the elements already in primes.



        • If yes, isPrime = false and break the for loop for j by j=primesLength

        • If not, isPrime = true



      • If isPrime == true then add i to the array primes and check if number%i == 0



        • If number%i == 0% update the value of factor as factor = i


      • Return factor after looping through all the numbers below number


      My code:






      function problem3(number)
      let factor = 1;
      let primes = [2]; //array to store prime numbers

      for(let i=3; i<number; i=i+2) //Increment i by 2 to loop through only odd numbers
      let isPrime = true;
      let primesLength= primes.length;

      for(let j=0; j< primesLength; j++)
      if(i%primes[j]==0)
      isPrime = false;
      j=primesLength; //to break the for loop



      if(isPrime == true)
      primes.push(i);
      if(number%i == 0)
      factor = i;



      return factor;


      console.log(problem3(600851475143));





      It is working perfectly for small numbers, but is quite very slow for 600851475143. What should I change in this code to make the computation faster?










      share|improve this question









      New contributor




      Eagle is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      I am self-learning js and came across this problem(#3) from the Euler Project




      The prime factors of 13195 are 5, 7, 13 and 29.



      What is the largest prime factor of the number 600851475143 ?




      Logic:



      • Have an array primes to store all the prime numbers less than number


      • Loop through the odd numbers only below number to check for primes using i



      • Check if i is divisible by any of the elements already in primes.



        • If yes, isPrime = false and break the for loop for j by j=primesLength

        • If not, isPrime = true



      • If isPrime == true then add i to the array primes and check if number%i == 0



        • If number%i == 0% update the value of factor as factor = i


      • Return factor after looping through all the numbers below number


      My code:






      function problem3(number)
      let factor = 1;
      let primes = [2]; //array to store prime numbers

      for(let i=3; i<number; i=i+2) //Increment i by 2 to loop through only odd numbers
      let isPrime = true;
      let primesLength= primes.length;

      for(let j=0; j< primesLength; j++)
      if(i%primes[j]==0)
      isPrime = false;
      j=primesLength; //to break the for loop



      if(isPrime == true)
      primes.push(i);
      if(number%i == 0)
      factor = i;



      return factor;


      console.log(problem3(600851475143));





      It is working perfectly for small numbers, but is quite very slow for 600851475143. What should I change in this code to make the computation faster?






      function problem3(number)
      let factor = 1;
      let primes = [2]; //array to store prime numbers

      for(let i=3; i<number; i=i+2) //Increment i by 2 to loop through only odd numbers
      let isPrime = true;
      let primesLength= primes.length;

      for(let j=0; j< primesLength; j++)
      if(i%primes[j]==0)
      isPrime = false;
      j=primesLength; //to break the for loop



      if(isPrime == true)
      primes.push(i);
      if(number%i == 0)
      factor = i;



      return factor;


      console.log(problem3(600851475143));





      function problem3(number)
      let factor = 1;
      let primes = [2]; //array to store prime numbers

      for(let i=3; i<number; i=i+2) //Increment i by 2 to loop through only odd numbers
      let isPrime = true;
      let primesLength= primes.length;

      for(let j=0; j< primesLength; j++)
      if(i%primes[j]==0)
      isPrime = false;
      j=primesLength; //to break the for loop



      if(isPrime == true)
      primes.push(i);
      if(number%i == 0)
      factor = i;



      return factor;


      console.log(problem3(600851475143));






      javascript beginner programming-challenge time-limit-exceeded primes






      share|improve this question









      New contributor




      Eagle is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









      New contributor




      Eagle is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question








      edited 1 hour ago









      200_success

      131k17157422




      131k17157422






      New contributor




      Eagle is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 2 hours ago









      EagleEagle

      1085




      1085




      New contributor




      Eagle is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      Eagle is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      Eagle is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.




















          2 Answers
          2






          active

          oldest

          votes


















          3












          $begingroup$

          There are many questions about Project Euler 3 on this site already. The trick is to pick an algorithm that…



          • Reduces n whenever you find a factor, so that you don't need to consider factors anywhere near as large as 600851475143

          • Only finds prime factors, and never composite factors, so that you never need to explicitly test for primality.

          Your algorithm suffers on both criteria: the outer for loop goes all the way up to 600851475143 (which is insane), and you're testing each of those numbers for primality (which is incredibly computationally expensive).






          share|improve this answer









          $endgroup$




















            1












            $begingroup$

            The first problem is that you are trying to find all prime numbers under number. The number of prime numbers under x is approximately x/ln(x) which is around 22153972243.4 for our specific value of x



            This is way too big ! So even if you where capable of obtaining each of these prime numbers in constant time it would take too much time.



            This tells us this approach is most likely unfixable.






            share|improve this answer








            New contributor




            Jorge Fernández is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






            $endgroup$













              Your Answer






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              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              3












              $begingroup$

              There are many questions about Project Euler 3 on this site already. The trick is to pick an algorithm that…



              • Reduces n whenever you find a factor, so that you don't need to consider factors anywhere near as large as 600851475143

              • Only finds prime factors, and never composite factors, so that you never need to explicitly test for primality.

              Your algorithm suffers on both criteria: the outer for loop goes all the way up to 600851475143 (which is insane), and you're testing each of those numbers for primality (which is incredibly computationally expensive).






              share|improve this answer









              $endgroup$

















                3












                $begingroup$

                There are many questions about Project Euler 3 on this site already. The trick is to pick an algorithm that…



                • Reduces n whenever you find a factor, so that you don't need to consider factors anywhere near as large as 600851475143

                • Only finds prime factors, and never composite factors, so that you never need to explicitly test for primality.

                Your algorithm suffers on both criteria: the outer for loop goes all the way up to 600851475143 (which is insane), and you're testing each of those numbers for primality (which is incredibly computationally expensive).






                share|improve this answer









                $endgroup$















                  3












                  3








                  3





                  $begingroup$

                  There are many questions about Project Euler 3 on this site already. The trick is to pick an algorithm that…



                  • Reduces n whenever you find a factor, so that you don't need to consider factors anywhere near as large as 600851475143

                  • Only finds prime factors, and never composite factors, so that you never need to explicitly test for primality.

                  Your algorithm suffers on both criteria: the outer for loop goes all the way up to 600851475143 (which is insane), and you're testing each of those numbers for primality (which is incredibly computationally expensive).






                  share|improve this answer









                  $endgroup$



                  There are many questions about Project Euler 3 on this site already. The trick is to pick an algorithm that…



                  • Reduces n whenever you find a factor, so that you don't need to consider factors anywhere near as large as 600851475143

                  • Only finds prime factors, and never composite factors, so that you never need to explicitly test for primality.

                  Your algorithm suffers on both criteria: the outer for loop goes all the way up to 600851475143 (which is insane), and you're testing each of those numbers for primality (which is incredibly computationally expensive).







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 1 hour ago









                  200_success200_success

                  131k17157422




                  131k17157422























                      1












                      $begingroup$

                      The first problem is that you are trying to find all prime numbers under number. The number of prime numbers under x is approximately x/ln(x) which is around 22153972243.4 for our specific value of x



                      This is way too big ! So even if you where capable of obtaining each of these prime numbers in constant time it would take too much time.



                      This tells us this approach is most likely unfixable.






                      share|improve this answer








                      New contributor




                      Jorge Fernández is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.






                      $endgroup$

















                        1












                        $begingroup$

                        The first problem is that you are trying to find all prime numbers under number. The number of prime numbers under x is approximately x/ln(x) which is around 22153972243.4 for our specific value of x



                        This is way too big ! So even if you where capable of obtaining each of these prime numbers in constant time it would take too much time.



                        This tells us this approach is most likely unfixable.






                        share|improve this answer








                        New contributor




                        Jorge Fernández is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                        Check out our Code of Conduct.






                        $endgroup$















                          1












                          1








                          1





                          $begingroup$

                          The first problem is that you are trying to find all prime numbers under number. The number of prime numbers under x is approximately x/ln(x) which is around 22153972243.4 for our specific value of x



                          This is way too big ! So even if you where capable of obtaining each of these prime numbers in constant time it would take too much time.



                          This tells us this approach is most likely unfixable.






                          share|improve this answer








                          New contributor




                          Jorge Fernández is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                          Check out our Code of Conduct.






                          $endgroup$



                          The first problem is that you are trying to find all prime numbers under number. The number of prime numbers under x is approximately x/ln(x) which is around 22153972243.4 for our specific value of x



                          This is way too big ! So even if you where capable of obtaining each of these prime numbers in constant time it would take too much time.



                          This tells us this approach is most likely unfixable.







                          share|improve this answer








                          New contributor




                          Jorge Fernández is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                          Check out our Code of Conduct.









                          share|improve this answer



                          share|improve this answer






                          New contributor




                          Jorge Fernández is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                          Check out our Code of Conduct.









                          answered 1 hour ago









                          Jorge FernándezJorge Fernández

                          1645




                          1645




                          New contributor




                          Jorge Fernández is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                          Check out our Code of Conduct.





                          New contributor





                          Jorge Fernández is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                          Check out our Code of Conduct.






                          Jorge Fernández is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                          Check out our Code of Conduct.




















                              Eagle is a new contributor. Be nice, and check out our Code of Conduct.









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                              Eagle is a new contributor. Be nice, and check out our Code of Conduct.












                              Eagle is a new contributor. Be nice, and check out our Code of Conduct.











                              Eagle is a new contributor. Be nice, and check out our Code of Conduct.














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There's a third YouTube co-founder"سایت یوتیوب برای چندمین بار در ایران فیلتر شدنسخهٔ اصلیسالار کمانگر جوان آمریکایی ایرانی الاصل مدیر سایت یوتیوب شدنسخهٔ اصلیVideo websites pop up, invite postingsthe originalthe originalYouTube: Overnight success has sparked a backlashthe original"Me at the zoo"YouTube serves up 100 million videos a day onlinethe originalcomScore Releases May 2010 U.S. Online Video Rankingsthe originalYouTube hits 4 billion daily video viewsthe originalYouTube users uploading two days of video every minutethe originalEric Schmidt, Princeton Colloquium on Public & Int'l Affairsthe original«Streaming Dreams»نسخهٔ اصلیAlexa Traffic Rank for YouTube (three month average)the originalHelp! YouTube is killing my business!the originalUtube sues YouTubethe originalGoogle closes $A2b YouTube dealthe originalFlash moves on to smart phonesthe originalYouTube HTML5 Video Playerنسخهٔ اصلیYouTube HTML5 Video Playerthe originalGoogle tries freeing Web video with WebMthe originalVideo length for uploadingthe originalYouTube caps video lengths to reduce infringementthe originalAccount Types: Longer videosthe originalYouTube bumps video limit to 15 minutesthe originalUploading large files and resumable uploadingthe originalVideo Formats: File formatsthe originalGetting Started: File formatsthe originalThe quest for a new video codec in Flash 8the originalAdobe Flash Video File Format Specification Version 10.1the originalYouTube Mobile goes livethe originalYouTube videos go HD with a simple hackthe originalYouTube now supports 4k-resolution videosthe originalYouTube to get high-def 1080p playerthe original«Approximate YouTube Bitrates»نسخهٔ اصلی«Bigger and Better: Encoding for YouTube 720p HD»نسخهٔ اصلی«YouTube's 1080p – Failure Depends on How You Look At It»نسخهٔ اصلیYouTube in 3Dthe originalYouTube in 3D?the originalYouTube 3D Videosthe originalYouTube adds a dimension, 3D goggles not includedthe originalYouTube Adds Stereoscopic 3D Video Support (And 3D Vision Support, Too)the original«Sharing YouTube Videos»نسخهٔ اصلی«Downloading videos from YouTube is not supported, except for one instance when it is permitted.»نسخهٔ اصلی«Terms of Use, 5.B»نسخهٔ اصلی«Some YouTube videos get download option»نسخهٔ اصلی«YouTube looks out for content owners, disables video ripping»«Downloading videos from YouTube is not supported, except for one instance when it is permitted.»نسخهٔ اصلی«YouTube Hopes To Boost Revenue With Video Downloads»نسخهٔ اصلی«YouTube Mobile»نسخهٔ اصلی«YouTube Live on Apple TV Today; Coming to iPhone on June 29»نسخهٔ اصلی«Goodbye Flash: YouTube mobile goes HTML5 on iPhone and Android»نسخهٔ اصلی«YouTube Mobile Goes HTML5, Video Quality Beats Native Apps Hands Down»نسخهٔ اصلی«TiVo Getting YouTube Streaming Today»نسخهٔ اصلی«YouTube video comes to Wii and PlayStation 3 game consoles»نسخهٔ اصلی«Coming Up Next... YouTube on Your TV»نسخهٔ اصلی«Experience YouTube XL on the Big Screen»نسخهٔ اصلی«Xbox Live Getting Live TV, YouTube & Bing Voice Search»نسخهٔ اصلی«YouTube content locations»نسخهٔ اصلی«April fools: YouTube turns the world up-side-down»نسخهٔ اصلی«YouTube goes back to 1911 for April Fools' Day»نسخهٔ اصلی«Simon Cowell's bromance, the self-driving Nascar and Hungry Hippos for iPad... the best April Fools' gags»نسخهٔ اصلی"YouTube Announces It Will Shut Down""YouTube Adds Darude 'Sandstorm' Button To Its Videos For April Fools' Day"«Censorship fears rise as Iran blocks access to top websites»نسخهٔ اصلی«China 'blocks YouTube video site'»نسخهٔ اصلی«YouTube shut down in Morocco»نسخهٔ اصلی«Thailand blocks access to YouTube»نسخهٔ اصلی«Ban on YouTube lifted after deal»نسخهٔ اصلی«Google's Gatekeepers»نسخهٔ اصلی«Turkey goes into battle with Google»نسخهٔ اصلی«Turkey lifts two-year ban on YouTube»نسخهٔ اصلیسانسور در ترکیه به یوتیوب رسیدلغو فیلترینگ یوتیوب در ترکیه«Pakistan blocks YouTube website»نسخهٔ اصلی«Pakistan lifts the ban on YouTube»نسخهٔ اصلی«Pakistan blocks access to YouTube in internet crackdown»نسخهٔ اصلی«Watchdog urges Libya to stop blocking websites»نسخهٔ اصلی«YouTube»نسخهٔ اصلی«Due to abuses of religion, customs Emirates, YouTube is blocked in the UAE»نسخهٔ اصلی«Google Conquered The Web - An Ultimate Winner»نسخهٔ اصلی«100 million videos are viewed daily on YouTube»نسخهٔ اصلی«Harry and Charlie Davies-Carr: Web gets taste for biting baby»نسخهٔ اصلی«Meet YouTube's 224 million girl, Natalie Tran»نسخهٔ اصلی«YouTube to Double Down on Its 'Channel' Experiment»نسخهٔ اصلی«13 Some Media Companies Choose to Profit From Pirated YouTube Clips»نسخهٔ اصلی«Irate HK man unlikely Web hero»نسخهٔ اصلی«Web Guitar Wizard Revealed at Last»نسخهٔ اصلی«Charlie bit my finger – again!»نسخهٔ اصلی«Lowered Expectations: Web Redefines 'Quality'»نسخهٔ اصلی«YouTube's 50 Greatest Viral Videos»نسخهٔ اصلیYouTube Community Guidelinesthe original«Why did my YouTube account get closed down?»نسخهٔ اصلی«Why do I have a sanction on my account?»نسخهٔ اصلی«Is YouTube's three-strike rule fair to users?»نسخهٔ اصلی«Viacom will sue YouTube for $1bn»نسخهٔ اصلی«Mediaset Files EUR500 Million Suit Vs Google's YouTube»نسخهٔ اصلی«Premier League to take action against YouTube»نسخهٔ اصلی«YouTube law fight 'threatens net'»نسخهٔ اصلی«Google must divulge YouTube log»نسخهٔ اصلی«Google Told to Turn Over User Data of YouTube»نسخهٔ اصلی«US judge tosses out Viacom copyright suit against YouTube»نسخهٔ اصلی«Google and Viacom: YouTube copyright lawsuit back on»نسخهٔ اصلی«Woman can sue over YouTube clip de-posting»نسخهٔ اصلی«YouTube loses court battle over music clips»نسخهٔ اصلیYouTube to Test Software To Ease Licensing Fightsthe original«Press Statistics»نسخهٔ اصلی«Testing YouTube's Audio Content ID System»نسخهٔ اصلی«Content ID disputes»نسخهٔ اصلیYouTube Community Guidelinesthe originalYouTube criticized in Germany over anti-Semitic Nazi videosthe originalFury as YouTube carries sick Hillsboro video insultthe originalYouTube attacked by MPs over sex and violence footagethe originalAl-Awlaki's YouTube Videos Targeted by Rep. Weinerthe originalYouTube Withdraws Cleric's Videosthe originalYouTube is letting users decide on terrorism-related videosthe original«Time's Person of the Year: You»نسخهٔ اصلی«Our top 10 funniest YouTube comments – what are yours?»نسخهٔ اصلی«YouTube's worst comments blocked by filter»نسخهٔ اصلی«Site Info YouTube»نسخهٔ اصلیوبگاه YouTubeوبگاه موبایل YouTubeوووووو

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                              Rest API with Magento using PHP with example. Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?How to update product using magento client library for PHP?Oauth Error while extending Magento Rest APINot showing my custom api in wsdl(url) and web service list?Using Magento API(REST) via IXMLHTTPRequest COM ObjectHow to login in Magento website using REST APIREST api call for Guest userMagento API calling using HTML and javascriptUse API rest media management by storeView code (admin)Magento REST API Example ErrorsHow to log all rest api calls in magento2?How to update product using magento client library for PHP?