Unitary representations of finite groups over finite fields The 2019 Stack Overflow Developer Survey Results Are InClassification of finite complex reflection groupsIrreducible unitary representations of locally compact groups How does one compute induced representations for modular representations?On infinite-dimensional unitary representations of Kazhdan groupsRepresentations of reductive groups over local fields through parahoric inductionIn which fixed-point free representations is the sum of every 3 elements invertible?Decomposing representations of finite groupsWhich finite groups have no irreducible representations other than characters?Good source for representation of GL(n) over finite fields?Outer automorphism action on representations of $S_6$

Unitary representations of finite groups over finite fields



The 2019 Stack Overflow Developer Survey Results Are InClassification of finite complex reflection groupsIrreducible unitary representations of locally compact groups How does one compute induced representations for modular representations?On infinite-dimensional unitary representations of Kazhdan groupsRepresentations of reductive groups over local fields through parahoric inductionIn which fixed-point free representations is the sum of every 3 elements invertible?Decomposing representations of finite groupsWhich finite groups have no irreducible representations other than characters?Good source for representation of GL(n) over finite fields?Outer automorphism action on representations of $S_6$










6












$begingroup$


I would like to learn the basic theory of unitary representations of finite groups over finite fields.
Here, the unitary group $operatornameGU(n,mathbbF_q^2)$ consists of all invertible transformations of $mathbbF_q^2^n$ that preserve the Hermitian form $langle x, y rangle = sum_i in [n] x_i y_i^q$, and "unitary representation" means a group homomorphism $rho colon G to operatornameGU(n,mathbbF_q^2)$.
This is a special case of the usual notion of a representation $rho colon G to operatornameGL(n,mathbbF_q^2)$.



Over the complex numbers, every representation $rho colon G to operatornameGL(n,mathbbC)$ of a finite group $G$ is similar to a unitary representation $rho' colon G to operatornameGU(n,mathbbC)$, in the sense that there is an invertible operator $M$ such that $rho'(g) = Mrho(g) M^-1$ for every $g in G$.
In this sense and others, the theory of unitary representations over $mathbbC$ is essentially the same as that of ordinary representations.



However, over finite fields the notions are distinct.
If $G$ is a finite group and $rho colon G to operatornameGL(n,mathbbF_q^2)$ is a representation, there might not be an invertible operator $M$ such that $M rho(g) M^-1 in operatornameGU(n,mathbbF_q^2)$ for every $g in G$.
For example, $mathbbZ_5$ has a faithful 2-dimensional representation over $mathbbF_3^2$ that is not similar to any unitary representation, since 5 divides $|operatornameGL(2,mathbbF_3^2)|$ but not $|operatornameGU(2,mathbbF_3^2)|$.



Question:
Have unitary representations of finite groups over finite fields been systematically studied, and if so where can I learn the basics?



Here is one example of what I want to learn to do:



  1. Describe all the unitary representations of the dihedral group of order 8 when $q=11$.

At the moment I do not even know how to:



  1. Describe all the unitary representations of $mathbbZ_2 times mathbbZ_2$ when $q=3$.

Some other things I want to learn include:



  1. Where Maschke's Theorem holds (i.e. $(|G|,q) = 1$ so that $mathbbF_q^2[G]$ is semisimple), does every unitary representation decompose as an orthogonal direct sum of irreducible unitary subrepresentations?


  2. Again where Maschke's Theorem holds, is there any analogue of the Peter-Weyl Theorem to give the space $L^2(G)$ of functions $f colon G to mathbbF_q^2$ an orthogonal basis consisting of matrix elements for irreducible unitary representations?


  3. What are some conditions for a modular representation to be similar to a unitary representation? (i.e. which subgroups of $operatornameGL(n,mathbbF_q^2)$ are conjugate with subgroups of $operatornameGU(n,mathbbF_q^2)$?)


Bonus for answers understandable to a humble analyst.










share|cite|improve this question









New contributor




Joey Iverson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$











  • $begingroup$
    Notice that finite-dimensional unitary representations are automatically semisimple; a minimal stable non-$0$ subspace is irreducible, and its orthogonal complement has smaller dimension. A similar argument shows that every semisimple unitary representation is an orthogonal direct sum of irreducibles.
    $endgroup$
    – LSpice
    4 hours ago











  • $begingroup$
    I think that a subgroup of $operatornameGL(n, mathbb F_q^2)$ is conjugate to a subgroup of $operatornameGU(n, mathbb F_q^2/mathbb F_q)$ if and only if it commutes with a torus of the form $(mathbb F_q^2^times)^n$.
    $endgroup$
    – LSpice
    4 hours ago










  • $begingroup$
    $mathbb F_3[C_2 times C_2]$ is the orthogonal direct sum $mathbb F_3(1, 1) oplus mathbb F_3(1, -1) oplus mathbb F_3(-1, 1) oplus mathbb F_3(-1, -1)$, where $(a, b)$ denotes the homomorphism $C_2 times C_2 to mathbb F_3^times$ given by $(m, n) mapsto a^m b^n$. The decomposition of the group algebra is guaranteed to capture all irreducible unitaries since, as usual, for an irreducible unitary representation $V$ of $G$, $V otimes V^*$ embeds in $mathbb F_q^2[G]$ by $v otimes v^* mapsto g mapsto langle v^*, gcdot vrangle$.
    $endgroup$
    – LSpice
    4 hours ago
















6












$begingroup$


I would like to learn the basic theory of unitary representations of finite groups over finite fields.
Here, the unitary group $operatornameGU(n,mathbbF_q^2)$ consists of all invertible transformations of $mathbbF_q^2^n$ that preserve the Hermitian form $langle x, y rangle = sum_i in [n] x_i y_i^q$, and "unitary representation" means a group homomorphism $rho colon G to operatornameGU(n,mathbbF_q^2)$.
This is a special case of the usual notion of a representation $rho colon G to operatornameGL(n,mathbbF_q^2)$.



Over the complex numbers, every representation $rho colon G to operatornameGL(n,mathbbC)$ of a finite group $G$ is similar to a unitary representation $rho' colon G to operatornameGU(n,mathbbC)$, in the sense that there is an invertible operator $M$ such that $rho'(g) = Mrho(g) M^-1$ for every $g in G$.
In this sense and others, the theory of unitary representations over $mathbbC$ is essentially the same as that of ordinary representations.



However, over finite fields the notions are distinct.
If $G$ is a finite group and $rho colon G to operatornameGL(n,mathbbF_q^2)$ is a representation, there might not be an invertible operator $M$ such that $M rho(g) M^-1 in operatornameGU(n,mathbbF_q^2)$ for every $g in G$.
For example, $mathbbZ_5$ has a faithful 2-dimensional representation over $mathbbF_3^2$ that is not similar to any unitary representation, since 5 divides $|operatornameGL(2,mathbbF_3^2)|$ but not $|operatornameGU(2,mathbbF_3^2)|$.



Question:
Have unitary representations of finite groups over finite fields been systematically studied, and if so where can I learn the basics?



Here is one example of what I want to learn to do:



  1. Describe all the unitary representations of the dihedral group of order 8 when $q=11$.

At the moment I do not even know how to:



  1. Describe all the unitary representations of $mathbbZ_2 times mathbbZ_2$ when $q=3$.

Some other things I want to learn include:



  1. Where Maschke's Theorem holds (i.e. $(|G|,q) = 1$ so that $mathbbF_q^2[G]$ is semisimple), does every unitary representation decompose as an orthogonal direct sum of irreducible unitary subrepresentations?


  2. Again where Maschke's Theorem holds, is there any analogue of the Peter-Weyl Theorem to give the space $L^2(G)$ of functions $f colon G to mathbbF_q^2$ an orthogonal basis consisting of matrix elements for irreducible unitary representations?


  3. What are some conditions for a modular representation to be similar to a unitary representation? (i.e. which subgroups of $operatornameGL(n,mathbbF_q^2)$ are conjugate with subgroups of $operatornameGU(n,mathbbF_q^2)$?)


Bonus for answers understandable to a humble analyst.










share|cite|improve this question









New contributor




Joey Iverson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$











  • $begingroup$
    Notice that finite-dimensional unitary representations are automatically semisimple; a minimal stable non-$0$ subspace is irreducible, and its orthogonal complement has smaller dimension. A similar argument shows that every semisimple unitary representation is an orthogonal direct sum of irreducibles.
    $endgroup$
    – LSpice
    4 hours ago











  • $begingroup$
    I think that a subgroup of $operatornameGL(n, mathbb F_q^2)$ is conjugate to a subgroup of $operatornameGU(n, mathbb F_q^2/mathbb F_q)$ if and only if it commutes with a torus of the form $(mathbb F_q^2^times)^n$.
    $endgroup$
    – LSpice
    4 hours ago










  • $begingroup$
    $mathbb F_3[C_2 times C_2]$ is the orthogonal direct sum $mathbb F_3(1, 1) oplus mathbb F_3(1, -1) oplus mathbb F_3(-1, 1) oplus mathbb F_3(-1, -1)$, where $(a, b)$ denotes the homomorphism $C_2 times C_2 to mathbb F_3^times$ given by $(m, n) mapsto a^m b^n$. The decomposition of the group algebra is guaranteed to capture all irreducible unitaries since, as usual, for an irreducible unitary representation $V$ of $G$, $V otimes V^*$ embeds in $mathbb F_q^2[G]$ by $v otimes v^* mapsto g mapsto langle v^*, gcdot vrangle$.
    $endgroup$
    – LSpice
    4 hours ago














6












6








6





$begingroup$


I would like to learn the basic theory of unitary representations of finite groups over finite fields.
Here, the unitary group $operatornameGU(n,mathbbF_q^2)$ consists of all invertible transformations of $mathbbF_q^2^n$ that preserve the Hermitian form $langle x, y rangle = sum_i in [n] x_i y_i^q$, and "unitary representation" means a group homomorphism $rho colon G to operatornameGU(n,mathbbF_q^2)$.
This is a special case of the usual notion of a representation $rho colon G to operatornameGL(n,mathbbF_q^2)$.



Over the complex numbers, every representation $rho colon G to operatornameGL(n,mathbbC)$ of a finite group $G$ is similar to a unitary representation $rho' colon G to operatornameGU(n,mathbbC)$, in the sense that there is an invertible operator $M$ such that $rho'(g) = Mrho(g) M^-1$ for every $g in G$.
In this sense and others, the theory of unitary representations over $mathbbC$ is essentially the same as that of ordinary representations.



However, over finite fields the notions are distinct.
If $G$ is a finite group and $rho colon G to operatornameGL(n,mathbbF_q^2)$ is a representation, there might not be an invertible operator $M$ such that $M rho(g) M^-1 in operatornameGU(n,mathbbF_q^2)$ for every $g in G$.
For example, $mathbbZ_5$ has a faithful 2-dimensional representation over $mathbbF_3^2$ that is not similar to any unitary representation, since 5 divides $|operatornameGL(2,mathbbF_3^2)|$ but not $|operatornameGU(2,mathbbF_3^2)|$.



Question:
Have unitary representations of finite groups over finite fields been systematically studied, and if so where can I learn the basics?



Here is one example of what I want to learn to do:



  1. Describe all the unitary representations of the dihedral group of order 8 when $q=11$.

At the moment I do not even know how to:



  1. Describe all the unitary representations of $mathbbZ_2 times mathbbZ_2$ when $q=3$.

Some other things I want to learn include:



  1. Where Maschke's Theorem holds (i.e. $(|G|,q) = 1$ so that $mathbbF_q^2[G]$ is semisimple), does every unitary representation decompose as an orthogonal direct sum of irreducible unitary subrepresentations?


  2. Again where Maschke's Theorem holds, is there any analogue of the Peter-Weyl Theorem to give the space $L^2(G)$ of functions $f colon G to mathbbF_q^2$ an orthogonal basis consisting of matrix elements for irreducible unitary representations?


  3. What are some conditions for a modular representation to be similar to a unitary representation? (i.e. which subgroups of $operatornameGL(n,mathbbF_q^2)$ are conjugate with subgroups of $operatornameGU(n,mathbbF_q^2)$?)


Bonus for answers understandable to a humble analyst.










share|cite|improve this question









New contributor




Joey Iverson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




I would like to learn the basic theory of unitary representations of finite groups over finite fields.
Here, the unitary group $operatornameGU(n,mathbbF_q^2)$ consists of all invertible transformations of $mathbbF_q^2^n$ that preserve the Hermitian form $langle x, y rangle = sum_i in [n] x_i y_i^q$, and "unitary representation" means a group homomorphism $rho colon G to operatornameGU(n,mathbbF_q^2)$.
This is a special case of the usual notion of a representation $rho colon G to operatornameGL(n,mathbbF_q^2)$.



Over the complex numbers, every representation $rho colon G to operatornameGL(n,mathbbC)$ of a finite group $G$ is similar to a unitary representation $rho' colon G to operatornameGU(n,mathbbC)$, in the sense that there is an invertible operator $M$ such that $rho'(g) = Mrho(g) M^-1$ for every $g in G$.
In this sense and others, the theory of unitary representations over $mathbbC$ is essentially the same as that of ordinary representations.



However, over finite fields the notions are distinct.
If $G$ is a finite group and $rho colon G to operatornameGL(n,mathbbF_q^2)$ is a representation, there might not be an invertible operator $M$ such that $M rho(g) M^-1 in operatornameGU(n,mathbbF_q^2)$ for every $g in G$.
For example, $mathbbZ_5$ has a faithful 2-dimensional representation over $mathbbF_3^2$ that is not similar to any unitary representation, since 5 divides $|operatornameGL(2,mathbbF_3^2)|$ but not $|operatornameGU(2,mathbbF_3^2)|$.



Question:
Have unitary representations of finite groups over finite fields been systematically studied, and if so where can I learn the basics?



Here is one example of what I want to learn to do:



  1. Describe all the unitary representations of the dihedral group of order 8 when $q=11$.

At the moment I do not even know how to:



  1. Describe all the unitary representations of $mathbbZ_2 times mathbbZ_2$ when $q=3$.

Some other things I want to learn include:



  1. Where Maschke's Theorem holds (i.e. $(|G|,q) = 1$ so that $mathbbF_q^2[G]$ is semisimple), does every unitary representation decompose as an orthogonal direct sum of irreducible unitary subrepresentations?


  2. Again where Maschke's Theorem holds, is there any analogue of the Peter-Weyl Theorem to give the space $L^2(G)$ of functions $f colon G to mathbbF_q^2$ an orthogonal basis consisting of matrix elements for irreducible unitary representations?


  3. What are some conditions for a modular representation to be similar to a unitary representation? (i.e. which subgroups of $operatornameGL(n,mathbbF_q^2)$ are conjugate with subgroups of $operatornameGU(n,mathbbF_q^2)$?)


Bonus for answers understandable to a humble analyst.







reference-request gr.group-theory rt.representation-theory finite-groups harmonic-analysis






share|cite|improve this question









New contributor




Joey Iverson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|cite|improve this question









New contributor




Joey Iverson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this question




share|cite|improve this question








edited 4 hours ago









YCor

29.1k486140




29.1k486140






New contributor




Joey Iverson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 5 hours ago









Joey IversonJoey Iverson

312




312




New contributor




Joey Iverson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Joey Iverson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Joey Iverson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











  • $begingroup$
    Notice that finite-dimensional unitary representations are automatically semisimple; a minimal stable non-$0$ subspace is irreducible, and its orthogonal complement has smaller dimension. A similar argument shows that every semisimple unitary representation is an orthogonal direct sum of irreducibles.
    $endgroup$
    – LSpice
    4 hours ago











  • $begingroup$
    I think that a subgroup of $operatornameGL(n, mathbb F_q^2)$ is conjugate to a subgroup of $operatornameGU(n, mathbb F_q^2/mathbb F_q)$ if and only if it commutes with a torus of the form $(mathbb F_q^2^times)^n$.
    $endgroup$
    – LSpice
    4 hours ago










  • $begingroup$
    $mathbb F_3[C_2 times C_2]$ is the orthogonal direct sum $mathbb F_3(1, 1) oplus mathbb F_3(1, -1) oplus mathbb F_3(-1, 1) oplus mathbb F_3(-1, -1)$, where $(a, b)$ denotes the homomorphism $C_2 times C_2 to mathbb F_3^times$ given by $(m, n) mapsto a^m b^n$. The decomposition of the group algebra is guaranteed to capture all irreducible unitaries since, as usual, for an irreducible unitary representation $V$ of $G$, $V otimes V^*$ embeds in $mathbb F_q^2[G]$ by $v otimes v^* mapsto g mapsto langle v^*, gcdot vrangle$.
    $endgroup$
    – LSpice
    4 hours ago

















  • $begingroup$
    Notice that finite-dimensional unitary representations are automatically semisimple; a minimal stable non-$0$ subspace is irreducible, and its orthogonal complement has smaller dimension. A similar argument shows that every semisimple unitary representation is an orthogonal direct sum of irreducibles.
    $endgroup$
    – LSpice
    4 hours ago











  • $begingroup$
    I think that a subgroup of $operatornameGL(n, mathbb F_q^2)$ is conjugate to a subgroup of $operatornameGU(n, mathbb F_q^2/mathbb F_q)$ if and only if it commutes with a torus of the form $(mathbb F_q^2^times)^n$.
    $endgroup$
    – LSpice
    4 hours ago










  • $begingroup$
    $mathbb F_3[C_2 times C_2]$ is the orthogonal direct sum $mathbb F_3(1, 1) oplus mathbb F_3(1, -1) oplus mathbb F_3(-1, 1) oplus mathbb F_3(-1, -1)$, where $(a, b)$ denotes the homomorphism $C_2 times C_2 to mathbb F_3^times$ given by $(m, n) mapsto a^m b^n$. The decomposition of the group algebra is guaranteed to capture all irreducible unitaries since, as usual, for an irreducible unitary representation $V$ of $G$, $V otimes V^*$ embeds in $mathbb F_q^2[G]$ by $v otimes v^* mapsto g mapsto langle v^*, gcdot vrangle$.
    $endgroup$
    – LSpice
    4 hours ago
















$begingroup$
Notice that finite-dimensional unitary representations are automatically semisimple; a minimal stable non-$0$ subspace is irreducible, and its orthogonal complement has smaller dimension. A similar argument shows that every semisimple unitary representation is an orthogonal direct sum of irreducibles.
$endgroup$
– LSpice
4 hours ago





$begingroup$
Notice that finite-dimensional unitary representations are automatically semisimple; a minimal stable non-$0$ subspace is irreducible, and its orthogonal complement has smaller dimension. A similar argument shows that every semisimple unitary representation is an orthogonal direct sum of irreducibles.
$endgroup$
– LSpice
4 hours ago













$begingroup$
I think that a subgroup of $operatornameGL(n, mathbb F_q^2)$ is conjugate to a subgroup of $operatornameGU(n, mathbb F_q^2/mathbb F_q)$ if and only if it commutes with a torus of the form $(mathbb F_q^2^times)^n$.
$endgroup$
– LSpice
4 hours ago




$begingroup$
I think that a subgroup of $operatornameGL(n, mathbb F_q^2)$ is conjugate to a subgroup of $operatornameGU(n, mathbb F_q^2/mathbb F_q)$ if and only if it commutes with a torus of the form $(mathbb F_q^2^times)^n$.
$endgroup$
– LSpice
4 hours ago












$begingroup$
$mathbb F_3[C_2 times C_2]$ is the orthogonal direct sum $mathbb F_3(1, 1) oplus mathbb F_3(1, -1) oplus mathbb F_3(-1, 1) oplus mathbb F_3(-1, -1)$, where $(a, b)$ denotes the homomorphism $C_2 times C_2 to mathbb F_3^times$ given by $(m, n) mapsto a^m b^n$. The decomposition of the group algebra is guaranteed to capture all irreducible unitaries since, as usual, for an irreducible unitary representation $V$ of $G$, $V otimes V^*$ embeds in $mathbb F_q^2[G]$ by $v otimes v^* mapsto g mapsto langle v^*, gcdot vrangle$.
$endgroup$
– LSpice
4 hours ago





$begingroup$
$mathbb F_3[C_2 times C_2]$ is the orthogonal direct sum $mathbb F_3(1, 1) oplus mathbb F_3(1, -1) oplus mathbb F_3(-1, 1) oplus mathbb F_3(-1, -1)$, where $(a, b)$ denotes the homomorphism $C_2 times C_2 to mathbb F_3^times$ given by $(m, n) mapsto a^m b^n$. The decomposition of the group algebra is guaranteed to capture all irreducible unitaries since, as usual, for an irreducible unitary representation $V$ of $G$, $V otimes V^*$ embeds in $mathbb F_q^2[G]$ by $v otimes v^* mapsto g mapsto langle v^*, gcdot vrangle$.
$endgroup$
– LSpice
4 hours ago











1 Answer
1






active

oldest

votes


















2












$begingroup$

We had to deal with this problem when classifying maximal subgroups of the finite classical groups, which is the aim of our book:



The Maximal Subgroups of the Low-Dimensional Finite Classical Groups, by
John N. Bray,
Derek F. Holt,
Colva M. Roney-Dougal.



The most difficult maximal subgroups to classify, are those in the so-called Aschbacher class $mathscr S$, consisting of absolutely irreducible subgroups that are almost simple mod scalars. Many of these arise as reductions of complex representations over finite fields. Tables of complex representations of groups that are close to simple are available up to dimension about $250$, but we needed to know which classical group the reduction lies in, which means identifying the fixed form.



We generally relied on Lemma 4.4.1 of the book, which says:



For a given absolutely irreducible representation over $mathbb F_q^2$ of a group $G$,
with Frobenius-Schur indicator $circ$, the image of $G$ under the representation consists of
isometries of a unitary form if and only if the action of the field automorphism
$sigma :x to x^q$ on the Brauer character is the same as complex conjugation.



In many cases, such as when $q$ is coprime to the group order, the Brauer character is just the ordinary complex character.



As an example, the reduction of the complex representation of degree $3$ of the $3$-fold cover $3.A_6$ of $A_6$ lies in $rm PSL(3,p)$ for primes $p equiv 1,4 bmod 15$, in $rm PSU(3,p)$ (as a subgroup of $rm PSL(3,p^2)$) when $p equiv 11,14 bmod 15$ (or when $p=5$), and in $rm PSL(3,p^2)$ without preserving a unitary form when $p equiv 2,3 bmod 5$.






share|cite|improve this answer











$endgroup$








  • 1




    $begingroup$
    Unless you think there's no risk of confusion, it may be worth it, for people like me who read "representation of a group over $mathbb F_q^2$" as "representation of (a group $G$ over $mathbb F_q^2$)", seeming to consider representations of algebraic groups, to re-phrase as "representation over $mathbb F_q^2$ of a group $G$", so that it's clear we're specifying the field of definition of the representation and not of the group (the latter meaningless anyway in the abstract setting considered).
    $endgroup$
    – LSpice
    2 hours ago










  • $begingroup$
    OK, I have reworded it, but I was quoting the lemma directly from the book!
    $endgroup$
    – Derek Holt
    1 hour ago











Your Answer





StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
);
);
, "mathjax-editing");

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "504"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);






Joey Iverson is a new contributor. Be nice, and check out our Code of Conduct.









draft saved

draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathoverflow.net%2fquestions%2f327823%2funitary-representations-of-finite-groups-over-finite-fields%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown

























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2












$begingroup$

We had to deal with this problem when classifying maximal subgroups of the finite classical groups, which is the aim of our book:



The Maximal Subgroups of the Low-Dimensional Finite Classical Groups, by
John N. Bray,
Derek F. Holt,
Colva M. Roney-Dougal.



The most difficult maximal subgroups to classify, are those in the so-called Aschbacher class $mathscr S$, consisting of absolutely irreducible subgroups that are almost simple mod scalars. Many of these arise as reductions of complex representations over finite fields. Tables of complex representations of groups that are close to simple are available up to dimension about $250$, but we needed to know which classical group the reduction lies in, which means identifying the fixed form.



We generally relied on Lemma 4.4.1 of the book, which says:



For a given absolutely irreducible representation over $mathbb F_q^2$ of a group $G$,
with Frobenius-Schur indicator $circ$, the image of $G$ under the representation consists of
isometries of a unitary form if and only if the action of the field automorphism
$sigma :x to x^q$ on the Brauer character is the same as complex conjugation.



In many cases, such as when $q$ is coprime to the group order, the Brauer character is just the ordinary complex character.



As an example, the reduction of the complex representation of degree $3$ of the $3$-fold cover $3.A_6$ of $A_6$ lies in $rm PSL(3,p)$ for primes $p equiv 1,4 bmod 15$, in $rm PSU(3,p)$ (as a subgroup of $rm PSL(3,p^2)$) when $p equiv 11,14 bmod 15$ (or when $p=5$), and in $rm PSL(3,p^2)$ without preserving a unitary form when $p equiv 2,3 bmod 5$.






share|cite|improve this answer











$endgroup$








  • 1




    $begingroup$
    Unless you think there's no risk of confusion, it may be worth it, for people like me who read "representation of a group over $mathbb F_q^2$" as "representation of (a group $G$ over $mathbb F_q^2$)", seeming to consider representations of algebraic groups, to re-phrase as "representation over $mathbb F_q^2$ of a group $G$", so that it's clear we're specifying the field of definition of the representation and not of the group (the latter meaningless anyway in the abstract setting considered).
    $endgroup$
    – LSpice
    2 hours ago










  • $begingroup$
    OK, I have reworded it, but I was quoting the lemma directly from the book!
    $endgroup$
    – Derek Holt
    1 hour ago















2












$begingroup$

We had to deal with this problem when classifying maximal subgroups of the finite classical groups, which is the aim of our book:



The Maximal Subgroups of the Low-Dimensional Finite Classical Groups, by
John N. Bray,
Derek F. Holt,
Colva M. Roney-Dougal.



The most difficult maximal subgroups to classify, are those in the so-called Aschbacher class $mathscr S$, consisting of absolutely irreducible subgroups that are almost simple mod scalars. Many of these arise as reductions of complex representations over finite fields. Tables of complex representations of groups that are close to simple are available up to dimension about $250$, but we needed to know which classical group the reduction lies in, which means identifying the fixed form.



We generally relied on Lemma 4.4.1 of the book, which says:



For a given absolutely irreducible representation over $mathbb F_q^2$ of a group $G$,
with Frobenius-Schur indicator $circ$, the image of $G$ under the representation consists of
isometries of a unitary form if and only if the action of the field automorphism
$sigma :x to x^q$ on the Brauer character is the same as complex conjugation.



In many cases, such as when $q$ is coprime to the group order, the Brauer character is just the ordinary complex character.



As an example, the reduction of the complex representation of degree $3$ of the $3$-fold cover $3.A_6$ of $A_6$ lies in $rm PSL(3,p)$ for primes $p equiv 1,4 bmod 15$, in $rm PSU(3,p)$ (as a subgroup of $rm PSL(3,p^2)$) when $p equiv 11,14 bmod 15$ (or when $p=5$), and in $rm PSL(3,p^2)$ without preserving a unitary form when $p equiv 2,3 bmod 5$.






share|cite|improve this answer











$endgroup$








  • 1




    $begingroup$
    Unless you think there's no risk of confusion, it may be worth it, for people like me who read "representation of a group over $mathbb F_q^2$" as "representation of (a group $G$ over $mathbb F_q^2$)", seeming to consider representations of algebraic groups, to re-phrase as "representation over $mathbb F_q^2$ of a group $G$", so that it's clear we're specifying the field of definition of the representation and not of the group (the latter meaningless anyway in the abstract setting considered).
    $endgroup$
    – LSpice
    2 hours ago










  • $begingroup$
    OK, I have reworded it, but I was quoting the lemma directly from the book!
    $endgroup$
    – Derek Holt
    1 hour ago













2












2








2





$begingroup$

We had to deal with this problem when classifying maximal subgroups of the finite classical groups, which is the aim of our book:



The Maximal Subgroups of the Low-Dimensional Finite Classical Groups, by
John N. Bray,
Derek F. Holt,
Colva M. Roney-Dougal.



The most difficult maximal subgroups to classify, are those in the so-called Aschbacher class $mathscr S$, consisting of absolutely irreducible subgroups that are almost simple mod scalars. Many of these arise as reductions of complex representations over finite fields. Tables of complex representations of groups that are close to simple are available up to dimension about $250$, but we needed to know which classical group the reduction lies in, which means identifying the fixed form.



We generally relied on Lemma 4.4.1 of the book, which says:



For a given absolutely irreducible representation over $mathbb F_q^2$ of a group $G$,
with Frobenius-Schur indicator $circ$, the image of $G$ under the representation consists of
isometries of a unitary form if and only if the action of the field automorphism
$sigma :x to x^q$ on the Brauer character is the same as complex conjugation.



In many cases, such as when $q$ is coprime to the group order, the Brauer character is just the ordinary complex character.



As an example, the reduction of the complex representation of degree $3$ of the $3$-fold cover $3.A_6$ of $A_6$ lies in $rm PSL(3,p)$ for primes $p equiv 1,4 bmod 15$, in $rm PSU(3,p)$ (as a subgroup of $rm PSL(3,p^2)$) when $p equiv 11,14 bmod 15$ (or when $p=5$), and in $rm PSL(3,p^2)$ without preserving a unitary form when $p equiv 2,3 bmod 5$.






share|cite|improve this answer











$endgroup$



We had to deal with this problem when classifying maximal subgroups of the finite classical groups, which is the aim of our book:



The Maximal Subgroups of the Low-Dimensional Finite Classical Groups, by
John N. Bray,
Derek F. Holt,
Colva M. Roney-Dougal.



The most difficult maximal subgroups to classify, are those in the so-called Aschbacher class $mathscr S$, consisting of absolutely irreducible subgroups that are almost simple mod scalars. Many of these arise as reductions of complex representations over finite fields. Tables of complex representations of groups that are close to simple are available up to dimension about $250$, but we needed to know which classical group the reduction lies in, which means identifying the fixed form.



We generally relied on Lemma 4.4.1 of the book, which says:



For a given absolutely irreducible representation over $mathbb F_q^2$ of a group $G$,
with Frobenius-Schur indicator $circ$, the image of $G$ under the representation consists of
isometries of a unitary form if and only if the action of the field automorphism
$sigma :x to x^q$ on the Brauer character is the same as complex conjugation.



In many cases, such as when $q$ is coprime to the group order, the Brauer character is just the ordinary complex character.



As an example, the reduction of the complex representation of degree $3$ of the $3$-fold cover $3.A_6$ of $A_6$ lies in $rm PSL(3,p)$ for primes $p equiv 1,4 bmod 15$, in $rm PSU(3,p)$ (as a subgroup of $rm PSL(3,p^2)$) when $p equiv 11,14 bmod 15$ (or when $p=5$), and in $rm PSL(3,p^2)$ without preserving a unitary form when $p equiv 2,3 bmod 5$.







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited 1 hour ago

























answered 3 hours ago









Derek HoltDerek Holt

27.4k464112




27.4k464112







  • 1




    $begingroup$
    Unless you think there's no risk of confusion, it may be worth it, for people like me who read "representation of a group over $mathbb F_q^2$" as "representation of (a group $G$ over $mathbb F_q^2$)", seeming to consider representations of algebraic groups, to re-phrase as "representation over $mathbb F_q^2$ of a group $G$", so that it's clear we're specifying the field of definition of the representation and not of the group (the latter meaningless anyway in the abstract setting considered).
    $endgroup$
    – LSpice
    2 hours ago










  • $begingroup$
    OK, I have reworded it, but I was quoting the lemma directly from the book!
    $endgroup$
    – Derek Holt
    1 hour ago












  • 1




    $begingroup$
    Unless you think there's no risk of confusion, it may be worth it, for people like me who read "representation of a group over $mathbb F_q^2$" as "representation of (a group $G$ over $mathbb F_q^2$)", seeming to consider representations of algebraic groups, to re-phrase as "representation over $mathbb F_q^2$ of a group $G$", so that it's clear we're specifying the field of definition of the representation and not of the group (the latter meaningless anyway in the abstract setting considered).
    $endgroup$
    – LSpice
    2 hours ago










  • $begingroup$
    OK, I have reworded it, but I was quoting the lemma directly from the book!
    $endgroup$
    – Derek Holt
    1 hour ago







1




1




$begingroup$
Unless you think there's no risk of confusion, it may be worth it, for people like me who read "representation of a group over $mathbb F_q^2$" as "representation of (a group $G$ over $mathbb F_q^2$)", seeming to consider representations of algebraic groups, to re-phrase as "representation over $mathbb F_q^2$ of a group $G$", so that it's clear we're specifying the field of definition of the representation and not of the group (the latter meaningless anyway in the abstract setting considered).
$endgroup$
– LSpice
2 hours ago




$begingroup$
Unless you think there's no risk of confusion, it may be worth it, for people like me who read "representation of a group over $mathbb F_q^2$" as "representation of (a group $G$ over $mathbb F_q^2$)", seeming to consider representations of algebraic groups, to re-phrase as "representation over $mathbb F_q^2$ of a group $G$", so that it's clear we're specifying the field of definition of the representation and not of the group (the latter meaningless anyway in the abstract setting considered).
$endgroup$
– LSpice
2 hours ago












$begingroup$
OK, I have reworded it, but I was quoting the lemma directly from the book!
$endgroup$
– Derek Holt
1 hour ago




$begingroup$
OK, I have reworded it, but I was quoting the lemma directly from the book!
$endgroup$
– Derek Holt
1 hour ago










Joey Iverson is a new contributor. Be nice, and check out our Code of Conduct.









draft saved

draft discarded


















Joey Iverson is a new contributor. Be nice, and check out our Code of Conduct.












Joey Iverson is a new contributor. Be nice, and check out our Code of Conduct.











Joey Iverson is a new contributor. Be nice, and check out our Code of Conduct.














Thanks for contributing an answer to MathOverflow!


  • Please be sure to answer the question. Provide details and share your research!

But avoid


  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.

Use MathJax to format equations. MathJax reference.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathoverflow.net%2fquestions%2f327823%2funitary-representations-of-finite-groups-over-finite-fields%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

یوتیوب محتویات پیشینه[ویرایش] فناوری‌های ویدئویی[ویرایش] شوخی‌های آوریل[ویرایش] سانسور و فیلترینگ[ویرایش] آمار و ارقامی از یوتیوب[ویرایش] تأثیر اجتماعی[ویرایش] سیاست اجتماعی[ویرایش] نمودارها[ویرایش] یادداشت‌ها[ویرایش] پانویس[ویرایش] پیوند به بیرون[ویرایش] منوی ناوبریبررسی شده‌استYouTube.com[بروزرسانی]"Youtube.com Site Info""زبان‌های یوتیوب""Surprise! There's a third YouTube co-founder"سایت یوتیوب برای چندمین بار در ایران فیلتر شدنسخهٔ اصلیسالار کمانگر جوان آمریکایی ایرانی الاصل مدیر سایت یوتیوب شدنسخهٔ اصلیVideo websites pop up, invite postingsthe originalthe originalYouTube: Overnight success has sparked a backlashthe original"Me at the zoo"YouTube serves up 100 million videos a day onlinethe originalcomScore Releases May 2010 U.S. Online Video Rankingsthe originalYouTube hits 4 billion daily video viewsthe originalYouTube users uploading two days of video every minutethe originalEric Schmidt, Princeton Colloquium on Public & Int'l Affairsthe original«Streaming Dreams»نسخهٔ اصلیAlexa Traffic Rank for YouTube (three month average)the originalHelp! YouTube is killing my business!the originalUtube sues YouTubethe originalGoogle closes $A2b YouTube dealthe originalFlash moves on to smart phonesthe originalYouTube HTML5 Video Playerنسخهٔ اصلیYouTube HTML5 Video Playerthe originalGoogle tries freeing Web video with WebMthe originalVideo length for uploadingthe originalYouTube caps video lengths to reduce infringementthe originalAccount Types: Longer videosthe originalYouTube bumps video limit to 15 minutesthe originalUploading large files and resumable uploadingthe originalVideo Formats: File formatsthe originalGetting Started: File formatsthe originalThe quest for a new video codec in Flash 8the originalAdobe Flash Video File Format Specification Version 10.1the originalYouTube Mobile goes livethe originalYouTube videos go HD with a simple hackthe originalYouTube now supports 4k-resolution videosthe originalYouTube to get high-def 1080p playerthe original«Approximate YouTube Bitrates»نسخهٔ اصلی«Bigger and Better: Encoding for YouTube 720p HD»نسخهٔ اصلی«YouTube's 1080p – Failure Depends on How You Look At It»نسخهٔ اصلیYouTube in 3Dthe originalYouTube in 3D?the originalYouTube 3D Videosthe originalYouTube adds a dimension, 3D goggles not includedthe originalYouTube Adds Stereoscopic 3D Video Support (And 3D Vision Support, Too)the original«Sharing YouTube Videos»نسخهٔ اصلی«Downloading videos from YouTube is not supported, except for one instance when it is permitted.»نسخهٔ اصلی«Terms of Use, 5.B»نسخهٔ اصلی«Some YouTube videos get download option»نسخهٔ اصلی«YouTube looks out for content owners, disables video ripping»«Downloading videos from YouTube is not supported, except for one instance when it is permitted.»نسخهٔ اصلی«YouTube Hopes To Boost Revenue With Video Downloads»نسخهٔ اصلی«YouTube Mobile»نسخهٔ اصلی«YouTube Live on Apple TV Today; Coming to iPhone on June 29»نسخهٔ اصلی«Goodbye Flash: YouTube mobile goes HTML5 on iPhone and Android»نسخهٔ اصلی«YouTube Mobile Goes HTML5, Video Quality Beats Native Apps Hands Down»نسخهٔ اصلی«TiVo Getting YouTube Streaming Today»نسخهٔ اصلی«YouTube video comes to Wii and PlayStation 3 game consoles»نسخهٔ اصلی«Coming Up Next... YouTube on Your TV»نسخهٔ اصلی«Experience YouTube XL on the Big Screen»نسخهٔ اصلی«Xbox Live Getting Live TV, YouTube & Bing Voice Search»نسخهٔ اصلی«YouTube content locations»نسخهٔ اصلی«April fools: YouTube turns the world up-side-down»نسخهٔ اصلی«YouTube goes back to 1911 for April Fools' Day»نسخهٔ اصلی«Simon Cowell's bromance, the self-driving Nascar and Hungry Hippos for iPad... the best April Fools' gags»نسخهٔ اصلی"YouTube Announces It Will Shut Down""YouTube Adds Darude 'Sandstorm' Button To Its Videos For April Fools' Day"«Censorship fears rise as Iran blocks access to top websites»نسخهٔ اصلی«China 'blocks YouTube video site'»نسخهٔ اصلی«YouTube shut down in Morocco»نسخهٔ اصلی«Thailand blocks access to YouTube»نسخهٔ اصلی«Ban on YouTube lifted after deal»نسخهٔ اصلی«Google's Gatekeepers»نسخهٔ اصلی«Turkey goes into battle with Google»نسخهٔ اصلی«Turkey lifts two-year ban on YouTube»نسخهٔ اصلیسانسور در ترکیه به یوتیوب رسیدلغو فیلترینگ یوتیوب در ترکیه«Pakistan blocks YouTube website»نسخهٔ اصلی«Pakistan lifts the ban on YouTube»نسخهٔ اصلی«Pakistan blocks access to YouTube in internet crackdown»نسخهٔ اصلی«Watchdog urges Libya to stop blocking websites»نسخهٔ اصلی«YouTube»نسخهٔ اصلی«Due to abuses of religion, customs Emirates, YouTube is blocked in the UAE»نسخهٔ اصلی«Google Conquered The Web - An Ultimate Winner»نسخهٔ اصلی«100 million videos are viewed daily on YouTube»نسخهٔ اصلی«Harry and Charlie Davies-Carr: Web gets taste for biting baby»نسخهٔ اصلی«Meet YouTube's 224 million girl, Natalie Tran»نسخهٔ اصلی«YouTube to Double Down on Its 'Channel' Experiment»نسخهٔ اصلی«13 Some Media Companies Choose to Profit From Pirated YouTube Clips»نسخهٔ اصلی«Irate HK man unlikely Web hero»نسخهٔ اصلی«Web Guitar Wizard Revealed at Last»نسخهٔ اصلی«Charlie bit my finger – again!»نسخهٔ اصلی«Lowered Expectations: Web Redefines 'Quality'»نسخهٔ اصلی«YouTube's 50 Greatest Viral Videos»نسخهٔ اصلیYouTube Community Guidelinesthe original«Why did my YouTube account get closed down?»نسخهٔ اصلی«Why do I have a sanction on my account?»نسخهٔ اصلی«Is YouTube's three-strike rule fair to users?»نسخهٔ اصلی«Viacom will sue YouTube for $1bn»نسخهٔ اصلی«Mediaset Files EUR500 Million Suit Vs Google's YouTube»نسخهٔ اصلی«Premier League to take action against YouTube»نسخهٔ اصلی«YouTube law fight 'threatens net'»نسخهٔ اصلی«Google must divulge YouTube log»نسخهٔ اصلی«Google Told to Turn Over User Data of YouTube»نسخهٔ اصلی«US judge tosses out Viacom copyright suit against YouTube»نسخهٔ اصلی«Google and Viacom: YouTube copyright lawsuit back on»نسخهٔ اصلی«Woman can sue over YouTube clip de-posting»نسخهٔ اصلی«YouTube loses court battle over music clips»نسخهٔ اصلیYouTube to Test Software To Ease Licensing Fightsthe original«Press Statistics»نسخهٔ اصلی«Testing YouTube's Audio Content ID System»نسخهٔ اصلی«Content ID disputes»نسخهٔ اصلیYouTube Community Guidelinesthe originalYouTube criticized in Germany over anti-Semitic Nazi videosthe originalFury as YouTube carries sick Hillsboro video insultthe originalYouTube attacked by MPs over sex and violence footagethe originalAl-Awlaki's YouTube Videos Targeted by Rep. Weinerthe originalYouTube Withdraws Cleric's Videosthe originalYouTube is letting users decide on terrorism-related videosthe original«Time's Person of the Year: You»نسخهٔ اصلی«Our top 10 funniest YouTube comments – what are yours?»نسخهٔ اصلی«YouTube's worst comments blocked by filter»نسخهٔ اصلی«Site Info YouTube»نسخهٔ اصلیوبگاه YouTubeوبگاه موبایل YouTubeوووووو

Magento 2 - Auto login with specific URL Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?Customer can't login - Page refreshes but nothing happensCustom Login page redirectURL to login with redirect URL after completionCustomer login is case sensitiveLogin with phone number or email address - Magento 1.9Magento 2: Set Customer Account Confirmation StatusCustomer auto connect from URLHow to call customer login form in the custom module action magento 2?Change of customer login error message magento2Referrer URL in modal login form

Rest API with Magento using PHP with example. Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?How to update product using magento client library for PHP?Oauth Error while extending Magento Rest APINot showing my custom api in wsdl(url) and web service list?Using Magento API(REST) via IXMLHTTPRequest COM ObjectHow to login in Magento website using REST APIREST api call for Guest userMagento API calling using HTML and javascriptUse API rest media management by storeView code (admin)Magento REST API Example ErrorsHow to log all rest api calls in magento2?How to update product using magento client library for PHP?