Is drag coefficient lowest at zero angle of attack? Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?How do insects decrease aircraft performance?How to draw NACA 6-Series Airfoils?How can the zero-lift drag coefficient (parasitic drag) be calculated?What is the relation between the Lift Coefficient and the Angle of Attack?Is it possible to fly horizontally with zero angle of attack?How to find trim condition of a sectional airfoil without knowing the angle of attack?What is the effect of flow separation on lift, pressure distribution and drag?How can the zero-lift drag coefficient (parasitic drag) be calculated?Do negative angles-of-attack create lift?How do you calculate the lift coefficient of an airfoil at zero angle of attack?Calculating induced drag approximation using XFoil generated parasitic dragDoes speed or angle of attack generally have the greatest impact on total induced drag?What's the theoretical background of the critical angle of attack?

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Is drag coefficient lowest at zero angle of attack?



Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
Unicorn Meta Zoo #1: Why another podcast?How do insects decrease aircraft performance?How to draw NACA 6-Series Airfoils?How can the zero-lift drag coefficient (parasitic drag) be calculated?What is the relation between the Lift Coefficient and the Angle of Attack?Is it possible to fly horizontally with zero angle of attack?How to find trim condition of a sectional airfoil without knowing the angle of attack?What is the effect of flow separation on lift, pressure distribution and drag?How can the zero-lift drag coefficient (parasitic drag) be calculated?Do negative angles-of-attack create lift?How do you calculate the lift coefficient of an airfoil at zero angle of attack?Calculating induced drag approximation using XFoil generated parasitic dragDoes speed or angle of attack generally have the greatest impact on total induced drag?What's the theoretical background of the critical angle of attack?










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The drag coefficient of a symmetric airfoil is lowest when its angle of attack is zero. I'm not sure if this is true in general.










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The drag coefficient of a symmetric airfoil is lowest when its angle of attack is zero. I'm not sure if this is true in general.










share|improve this question







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simple jack is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







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  • $begingroup$
    Welcome to Av.SE!
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1












1








1





$begingroup$


The drag coefficient of a symmetric airfoil is lowest when its angle of attack is zero. I'm not sure if this is true in general.










share|improve this question







New contributor




simple jack is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




The drag coefficient of a symmetric airfoil is lowest when its angle of attack is zero. I'm not sure if this is true in general.







aerodynamics airfoil drag angle-of-attack






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simple jack is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











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asked 6 hours ago









simple jacksimple jack

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103




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simple jack is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor





simple jack is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






simple jack is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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  • $begingroup$
    Welcome to Av.SE!
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    – Ralph J
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$begingroup$
Welcome to Av.SE!
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2 Answers
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$begingroup$

Obviously, drag should be smallest for symmetrical airfoils at zero angle of attack.



However, most airfoils have camber, and then the lowest drag is at positive lift coefficients in case of positive camber. Where that point is exactly depends on many parameters; in case of laminar airfoils even local imperfections can have a noticeable effect. Generally, the lowest drag can be found at the angle of attack where the stagnation point is exactly at the center of the leading edge, where the local curvature is highest. A deviation from this point will force the flow on one side to negotiate this point of highest curvature all by itself, resulting in a suction peak which will increase the losses in the boundary layer.



flap polar



This is a theoretical drag polar (calculated with XFOIL) of an airfoil with a 20% camber flap at different settings and a Reynolds number of 1.5 million. The laminar bucket is clearly visible and produces a range of lift coefficients with nearly identical drag. The small waviness at the lower end of the laminar bucket is an artificial result of smoothing the plot.



What is obvious is how camber shifts the area of minimum drag up and down. If you use the right side of the plot to find the angle of attack of minimum drag, you will find that this is not constant but goes down as flap angles go up. For the 0° flap polar it is at about -2° AoA. This is caused by the induced angle of attack which increases with the lift coefficient.



The 6-series NACA airfoils were the first to be systematically designed with the pressure distribution in mind, and the design lift coefficient is where the condition of the ideal stagnation point location is met. This is indicated by the digit right after the hyphen in the airfoil name: Divide this digit by 10 and you have the lift coefficient of minimum drag.



Example: The $63_1-412$ airfoil has its lowest drag at a lift coefficient of 0.4.



If you want to know the angle of attack with the lowest drag of a whole airplane, this is a very different matter and needs to include the drag due to lift, which is of course smallest at the zero lift polar point.






share|improve this answer









$endgroup$




















    0












    $begingroup$

    Yes, for a symmetrical lift generating airfoil this is true.



    The drag coefficient is computed by dividing the wetted area $A_w$ of the airfoil by its frontal area $A_f$ :



    $$ c_d = fracA_wA_f $$



    For non-symmetrical airfoils, the lowest drag coefficient is found at the angle of attack were the frontal area is at its smallest. For almost all the airfoils this is at 0 degrees AoA.






    share|improve this answer











    $endgroup$












    • $begingroup$
      It is not true for the Clark-Y airfoil.
      $endgroup$
      – simple jack
      5 hours ago










    • $begingroup$
      Frontal area is smallest? April 1st was two weeks ago!
      $endgroup$
      – Peter Kämpf
      1 hour ago











    Your Answer








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    2 Answers
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    2 Answers
    2






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    active

    oldest

    votes






    active

    oldest

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    2












    $begingroup$

    Obviously, drag should be smallest for symmetrical airfoils at zero angle of attack.



    However, most airfoils have camber, and then the lowest drag is at positive lift coefficients in case of positive camber. Where that point is exactly depends on many parameters; in case of laminar airfoils even local imperfections can have a noticeable effect. Generally, the lowest drag can be found at the angle of attack where the stagnation point is exactly at the center of the leading edge, where the local curvature is highest. A deviation from this point will force the flow on one side to negotiate this point of highest curvature all by itself, resulting in a suction peak which will increase the losses in the boundary layer.



    flap polar



    This is a theoretical drag polar (calculated with XFOIL) of an airfoil with a 20% camber flap at different settings and a Reynolds number of 1.5 million. The laminar bucket is clearly visible and produces a range of lift coefficients with nearly identical drag. The small waviness at the lower end of the laminar bucket is an artificial result of smoothing the plot.



    What is obvious is how camber shifts the area of minimum drag up and down. If you use the right side of the plot to find the angle of attack of minimum drag, you will find that this is not constant but goes down as flap angles go up. For the 0° flap polar it is at about -2° AoA. This is caused by the induced angle of attack which increases with the lift coefficient.



    The 6-series NACA airfoils were the first to be systematically designed with the pressure distribution in mind, and the design lift coefficient is where the condition of the ideal stagnation point location is met. This is indicated by the digit right after the hyphen in the airfoil name: Divide this digit by 10 and you have the lift coefficient of minimum drag.



    Example: The $63_1-412$ airfoil has its lowest drag at a lift coefficient of 0.4.



    If you want to know the angle of attack with the lowest drag of a whole airplane, this is a very different matter and needs to include the drag due to lift, which is of course smallest at the zero lift polar point.






    share|improve this answer









    $endgroup$

















      2












      $begingroup$

      Obviously, drag should be smallest for symmetrical airfoils at zero angle of attack.



      However, most airfoils have camber, and then the lowest drag is at positive lift coefficients in case of positive camber. Where that point is exactly depends on many parameters; in case of laminar airfoils even local imperfections can have a noticeable effect. Generally, the lowest drag can be found at the angle of attack where the stagnation point is exactly at the center of the leading edge, where the local curvature is highest. A deviation from this point will force the flow on one side to negotiate this point of highest curvature all by itself, resulting in a suction peak which will increase the losses in the boundary layer.



      flap polar



      This is a theoretical drag polar (calculated with XFOIL) of an airfoil with a 20% camber flap at different settings and a Reynolds number of 1.5 million. The laminar bucket is clearly visible and produces a range of lift coefficients with nearly identical drag. The small waviness at the lower end of the laminar bucket is an artificial result of smoothing the plot.



      What is obvious is how camber shifts the area of minimum drag up and down. If you use the right side of the plot to find the angle of attack of minimum drag, you will find that this is not constant but goes down as flap angles go up. For the 0° flap polar it is at about -2° AoA. This is caused by the induced angle of attack which increases with the lift coefficient.



      The 6-series NACA airfoils were the first to be systematically designed with the pressure distribution in mind, and the design lift coefficient is where the condition of the ideal stagnation point location is met. This is indicated by the digit right after the hyphen in the airfoil name: Divide this digit by 10 and you have the lift coefficient of minimum drag.



      Example: The $63_1-412$ airfoil has its lowest drag at a lift coefficient of 0.4.



      If you want to know the angle of attack with the lowest drag of a whole airplane, this is a very different matter and needs to include the drag due to lift, which is of course smallest at the zero lift polar point.






      share|improve this answer









      $endgroup$















        2












        2








        2





        $begingroup$

        Obviously, drag should be smallest for symmetrical airfoils at zero angle of attack.



        However, most airfoils have camber, and then the lowest drag is at positive lift coefficients in case of positive camber. Where that point is exactly depends on many parameters; in case of laminar airfoils even local imperfections can have a noticeable effect. Generally, the lowest drag can be found at the angle of attack where the stagnation point is exactly at the center of the leading edge, where the local curvature is highest. A deviation from this point will force the flow on one side to negotiate this point of highest curvature all by itself, resulting in a suction peak which will increase the losses in the boundary layer.



        flap polar



        This is a theoretical drag polar (calculated with XFOIL) of an airfoil with a 20% camber flap at different settings and a Reynolds number of 1.5 million. The laminar bucket is clearly visible and produces a range of lift coefficients with nearly identical drag. The small waviness at the lower end of the laminar bucket is an artificial result of smoothing the plot.



        What is obvious is how camber shifts the area of minimum drag up and down. If you use the right side of the plot to find the angle of attack of minimum drag, you will find that this is not constant but goes down as flap angles go up. For the 0° flap polar it is at about -2° AoA. This is caused by the induced angle of attack which increases with the lift coefficient.



        The 6-series NACA airfoils were the first to be systematically designed with the pressure distribution in mind, and the design lift coefficient is where the condition of the ideal stagnation point location is met. This is indicated by the digit right after the hyphen in the airfoil name: Divide this digit by 10 and you have the lift coefficient of minimum drag.



        Example: The $63_1-412$ airfoil has its lowest drag at a lift coefficient of 0.4.



        If you want to know the angle of attack with the lowest drag of a whole airplane, this is a very different matter and needs to include the drag due to lift, which is of course smallest at the zero lift polar point.






        share|improve this answer









        $endgroup$



        Obviously, drag should be smallest for symmetrical airfoils at zero angle of attack.



        However, most airfoils have camber, and then the lowest drag is at positive lift coefficients in case of positive camber. Where that point is exactly depends on many parameters; in case of laminar airfoils even local imperfections can have a noticeable effect. Generally, the lowest drag can be found at the angle of attack where the stagnation point is exactly at the center of the leading edge, where the local curvature is highest. A deviation from this point will force the flow on one side to negotiate this point of highest curvature all by itself, resulting in a suction peak which will increase the losses in the boundary layer.



        flap polar



        This is a theoretical drag polar (calculated with XFOIL) of an airfoil with a 20% camber flap at different settings and a Reynolds number of 1.5 million. The laminar bucket is clearly visible and produces a range of lift coefficients with nearly identical drag. The small waviness at the lower end of the laminar bucket is an artificial result of smoothing the plot.



        What is obvious is how camber shifts the area of minimum drag up and down. If you use the right side of the plot to find the angle of attack of minimum drag, you will find that this is not constant but goes down as flap angles go up. For the 0° flap polar it is at about -2° AoA. This is caused by the induced angle of attack which increases with the lift coefficient.



        The 6-series NACA airfoils were the first to be systematically designed with the pressure distribution in mind, and the design lift coefficient is where the condition of the ideal stagnation point location is met. This is indicated by the digit right after the hyphen in the airfoil name: Divide this digit by 10 and you have the lift coefficient of minimum drag.



        Example: The $63_1-412$ airfoil has its lowest drag at a lift coefficient of 0.4.



        If you want to know the angle of attack with the lowest drag of a whole airplane, this is a very different matter and needs to include the drag due to lift, which is of course smallest at the zero lift polar point.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 1 hour ago









        Peter KämpfPeter Kämpf

        162k12411656




        162k12411656





















            0












            $begingroup$

            Yes, for a symmetrical lift generating airfoil this is true.



            The drag coefficient is computed by dividing the wetted area $A_w$ of the airfoil by its frontal area $A_f$ :



            $$ c_d = fracA_wA_f $$



            For non-symmetrical airfoils, the lowest drag coefficient is found at the angle of attack were the frontal area is at its smallest. For almost all the airfoils this is at 0 degrees AoA.






            share|improve this answer











            $endgroup$












            • $begingroup$
              It is not true for the Clark-Y airfoil.
              $endgroup$
              – simple jack
              5 hours ago










            • $begingroup$
              Frontal area is smallest? April 1st was two weeks ago!
              $endgroup$
              – Peter Kämpf
              1 hour ago















            0












            $begingroup$

            Yes, for a symmetrical lift generating airfoil this is true.



            The drag coefficient is computed by dividing the wetted area $A_w$ of the airfoil by its frontal area $A_f$ :



            $$ c_d = fracA_wA_f $$



            For non-symmetrical airfoils, the lowest drag coefficient is found at the angle of attack were the frontal area is at its smallest. For almost all the airfoils this is at 0 degrees AoA.






            share|improve this answer











            $endgroup$












            • $begingroup$
              It is not true for the Clark-Y airfoil.
              $endgroup$
              – simple jack
              5 hours ago










            • $begingroup$
              Frontal area is smallest? April 1st was two weeks ago!
              $endgroup$
              – Peter Kämpf
              1 hour ago













            0












            0








            0





            $begingroup$

            Yes, for a symmetrical lift generating airfoil this is true.



            The drag coefficient is computed by dividing the wetted area $A_w$ of the airfoil by its frontal area $A_f$ :



            $$ c_d = fracA_wA_f $$



            For non-symmetrical airfoils, the lowest drag coefficient is found at the angle of attack were the frontal area is at its smallest. For almost all the airfoils this is at 0 degrees AoA.






            share|improve this answer











            $endgroup$



            Yes, for a symmetrical lift generating airfoil this is true.



            The drag coefficient is computed by dividing the wetted area $A_w$ of the airfoil by its frontal area $A_f$ :



            $$ c_d = fracA_wA_f $$



            For non-symmetrical airfoils, the lowest drag coefficient is found at the angle of attack were the frontal area is at its smallest. For almost all the airfoils this is at 0 degrees AoA.







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 4 hours ago









            simple jack

            103




            103










            answered 5 hours ago









            BrilsmurfffjeBrilsmurfffje

            3,41621536




            3,41621536











            • $begingroup$
              It is not true for the Clark-Y airfoil.
              $endgroup$
              – simple jack
              5 hours ago










            • $begingroup$
              Frontal area is smallest? April 1st was two weeks ago!
              $endgroup$
              – Peter Kämpf
              1 hour ago
















            • $begingroup$
              It is not true for the Clark-Y airfoil.
              $endgroup$
              – simple jack
              5 hours ago










            • $begingroup$
              Frontal area is smallest? April 1st was two weeks ago!
              $endgroup$
              – Peter Kämpf
              1 hour ago















            $begingroup$
            It is not true for the Clark-Y airfoil.
            $endgroup$
            – simple jack
            5 hours ago




            $begingroup$
            It is not true for the Clark-Y airfoil.
            $endgroup$
            – simple jack
            5 hours ago












            $begingroup$
            Frontal area is smallest? April 1st was two weeks ago!
            $endgroup$
            – Peter Kämpf
            1 hour ago




            $begingroup$
            Frontal area is smallest? April 1st was two weeks ago!
            $endgroup$
            – Peter Kämpf
            1 hour ago










            simple jack is a new contributor. Be nice, and check out our Code of Conduct.









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There's a third YouTube co-founder"سایت یوتیوب برای چندمین بار در ایران فیلتر شدنسخهٔ اصلیسالار کمانگر جوان آمریکایی ایرانی الاصل مدیر سایت یوتیوب شدنسخهٔ اصلیVideo websites pop up, invite postingsthe originalthe originalYouTube: Overnight success has sparked a backlashthe original"Me at the zoo"YouTube serves up 100 million videos a day onlinethe originalcomScore Releases May 2010 U.S. Online Video Rankingsthe originalYouTube hits 4 billion daily video viewsthe originalYouTube users uploading two days of video every minutethe originalEric Schmidt, Princeton Colloquium on Public & Int'l Affairsthe original«Streaming Dreams»نسخهٔ اصلیAlexa Traffic Rank for YouTube (three month average)the originalHelp! 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YouTube on Your TV»نسخهٔ اصلی«Experience YouTube XL on the Big Screen»نسخهٔ اصلی«Xbox Live Getting Live TV, YouTube & Bing Voice Search»نسخهٔ اصلی«YouTube content locations»نسخهٔ اصلی«April fools: YouTube turns the world up-side-down»نسخهٔ اصلی«YouTube goes back to 1911 for April Fools' Day»نسخهٔ اصلی«Simon Cowell's bromance, the self-driving Nascar and Hungry Hippos for iPad... the best April Fools' gags»نسخهٔ اصلی"YouTube Announces It Will Shut Down""YouTube Adds Darude 'Sandstorm' Button To Its Videos For April Fools' Day"«Censorship fears rise as Iran blocks access to top websites»نسخهٔ اصلی«China 'blocks YouTube video site'»نسخهٔ اصلی«YouTube shut down in Morocco»نسخهٔ اصلی«Thailand blocks access to YouTube»نسخهٔ اصلی«Ban on YouTube lifted after deal»نسخهٔ اصلی«Google's Gatekeepers»نسخهٔ اصلی«Turkey goes into battle with Google»نسخهٔ اصلی«Turkey lifts two-year ban on YouTube»نسخهٔ اصلیسانسور در ترکیه به یوتیوب رسیدلغو فیلترینگ یوتیوب در ترکیه«Pakistan blocks YouTube website»نسخهٔ اصلی«Pakistan lifts the ban on YouTube»نسخهٔ اصلی«Pakistan blocks access to YouTube in internet crackdown»نسخهٔ اصلی«Watchdog urges Libya to stop blocking websites»نسخهٔ اصلی«YouTube»نسخهٔ اصلی«Due to abuses of religion, customs Emirates, YouTube is blocked in the UAE»نسخهٔ اصلی«Google Conquered The Web - An Ultimate Winner»نسخهٔ اصلی«100 million videos are viewed daily on YouTube»نسخهٔ اصلی«Harry and Charlie Davies-Carr: Web gets taste for biting baby»نسخهٔ اصلی«Meet YouTube's 224 million girl, Natalie Tran»نسخهٔ اصلی«YouTube to Double Down on Its 'Channel' Experiment»نسخهٔ اصلی«13 Some Media Companies Choose to Profit From Pirated YouTube Clips»نسخهٔ اصلی«Irate HK man unlikely Web hero»نسخهٔ اصلی«Web Guitar Wizard Revealed at Last»نسخهٔ اصلی«Charlie bit my finger – again!»نسخهٔ اصلی«Lowered Expectations: Web Redefines 'Quality'»نسخهٔ اصلی«YouTube's 50 Greatest Viral Videos»نسخهٔ اصلیYouTube Community Guidelinesthe original«Why did my YouTube account get closed down?»نسخهٔ اصلی«Why do I have a sanction on my account?»نسخهٔ اصلی«Is YouTube's three-strike rule fair to users?»نسخهٔ اصلی«Viacom will sue YouTube for $1bn»نسخهٔ اصلی«Mediaset Files EUR500 Million Suit Vs Google's YouTube»نسخهٔ اصلی«Premier League to take action against YouTube»نسخهٔ اصلی«YouTube law fight 'threatens net'»نسخهٔ اصلی«Google must divulge YouTube log»نسخهٔ اصلی«Google Told to Turn Over User Data of YouTube»نسخهٔ اصلی«US judge tosses out Viacom copyright suit against YouTube»نسخهٔ اصلی«Google and Viacom: YouTube copyright lawsuit back on»نسخهٔ اصلی«Woman can sue over YouTube clip de-posting»نسخهٔ اصلی«YouTube loses court battle over music clips»نسخهٔ اصلیYouTube to Test Software To Ease Licensing Fightsthe original«Press Statistics»نسخهٔ اصلی«Testing YouTube's Audio Content ID System»نسخهٔ اصلی«Content ID disputes»نسخهٔ اصلیYouTube Community Guidelinesthe originalYouTube criticized in Germany over anti-Semitic Nazi videosthe originalFury as YouTube carries sick Hillsboro video insultthe originalYouTube attacked by MPs over sex and violence footagethe originalAl-Awlaki's YouTube Videos Targeted by Rep. Weinerthe originalYouTube Withdraws Cleric's Videosthe originalYouTube is letting users decide on terrorism-related videosthe original«Time's Person of the Year: You»نسخهٔ اصلی«Our top 10 funniest YouTube comments – what are yours?»نسخهٔ اصلی«YouTube's worst comments blocked by filter»نسخهٔ اصلی«Site Info YouTube»نسخهٔ اصلیوبگاه YouTubeوبگاه موبایل YouTubeوووووو

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