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Pulling the rope with one hand is as heavy as with two hands?
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Pulling the rope with one hand is as heavy as with two hands?
The Twins with a Different AgeFind the magnet among the two rodsA semi truck weighing exactly 10,000 poundsThe largest and smallest value with 4 resistors
$begingroup$
There is this box, having two holes, and the ropes going through each of them.
I try to pull the left rope with my left hand... And it's heavy...
Then I try to pull the right rope with my right hand... It's also heavy, as heavy as before.
Ok so... I think both ropes are directly connected to a single weight.
So I try to pull both ropes with my both hands, hoping the weight will be lighter by $50%$...
But... I'm wrong... It's as heavy as before!
Ah, of course. There are two weights. Each rope is connected to different weight...
Yes, that makes sense!
Let's open this box to prove that I'm right.
...
Wait... What?! There is only one weight there?! Wow, what an amazing contraption!
So, do you know how can this be happening?
physics
asked 2 hours ago
athinathin
8,92922979
$endgroup$
add a comment |
$begingroup$
There is this box, having two holes, and the ropes going through each of them.
I try to pull the left rope with my left hand... And it's heavy...
Then I try to pull the right rope with my right hand... It's also heavy, as heavy as before.
Ok so... I think both ropes are directly connected to a single weight.
So I try to pull both ropes with my both hands, hoping the weight will be lighter by $50%$...
But... I'm wrong... It's as heavy as before!
Ah, of course. There are two weights. Each rope is connected to different weight...
Yes, that makes sense!
Let's open this box to prove that I'm right.
...
Wait... What?! There is only one weight there?! Wow, what an amazing contraption!
So, do you know how can this be happening?
physics
asked 2 hours ago
athinathin
8,92922979
$endgroup$
$begingroup$
Is this unexpected?
$endgroup$
– noedne
2 hours ago
$begingroup$
Do you measure how hard it is to lift the weight or to keep it in a high position, or both?
$endgroup$
– Arnaud Mortier
2 hours ago
$begingroup$
@noedne Ten people can lift a small car, one person cannot.
$endgroup$
– Arnaud Mortier
2 hours ago
$begingroup$
@noedne Given the final contraption, it's expected to behave as the story.
$endgroup$
– athin
2 hours ago
1
$begingroup$
@ArnaudMortier The measurement can be exact. Say, you need $x$ Newton to perform those $3$ pullings. (Well, for the third one, it should be $2x$ Newton in total as using both of hands $= x + x$.)
$endgroup$
– athin
2 hours ago
add a comment |
$begingroup$
There is this box, having two holes, and the ropes going through each of them.
I try to pull the left rope with my left hand... And it's heavy...
Then I try to pull the right rope with my right hand... It's also heavy, as heavy as before.
Ok so... I think both ropes are directly connected to a single weight.
So I try to pull both ropes with my both hands, hoping the weight will be lighter by $50%$...
But... I'm wrong... It's as heavy as before!
Ah, of course. There are two weights. Each rope is connected to different weight...
Yes, that makes sense!
Let's open this box to prove that I'm right.
...
Wait... What?! There is only one weight there?! Wow, what an amazing contraption!
So, do you know how can this be happening?
physics
asked 2 hours ago
athinathin
8,92922979
$endgroup$
There is this box, having two holes, and the ropes going through each of them.
I try to pull the left rope with my left hand... And it's heavy...
Then I try to pull the right rope with my right hand... It's also heavy, as heavy as before.
Ok so... I think both ropes are directly connected to a single weight.
So I try to pull both ropes with my both hands, hoping the weight will be lighter by $50%$...
But... I'm wrong... It's as heavy as before!
Ah, of course. There are two weights. Each rope is connected to different weight...
Yes, that makes sense!
Let's open this box to prove that I'm right.
...
Wait... What?! There is only one weight there?! Wow, what an amazing contraption!
So, do you know how can this be happening?
physics
physics
asked 2 hours ago
athinathin
8,92922979
asked 2 hours ago
athinathin
8,92922979
asked 2 hours ago
athinathin
8,92922979
asked 2 hours ago
athinathin
8,92922979
asked 2 hours ago
athinathin
8,92922979
8,92922979
$begingroup$
Is this unexpected?
$endgroup$
– noedne
2 hours ago
$begingroup$
Do you measure how hard it is to lift the weight or to keep it in a high position, or both?
$endgroup$
– Arnaud Mortier
2 hours ago
$begingroup$
@noedne Ten people can lift a small car, one person cannot.
$endgroup$
– Arnaud Mortier
2 hours ago
$begingroup$
@noedne Given the final contraption, it's expected to behave as the story.
$endgroup$
– athin
2 hours ago
1
$begingroup$
@ArnaudMortier The measurement can be exact. Say, you need $x$ Newton to perform those $3$ pullings. (Well, for the third one, it should be $2x$ Newton in total as using both of hands $= x + x$.)
$endgroup$
– athin
2 hours ago
add a comment |
$begingroup$
Is this unexpected?
$endgroup$
– noedne
2 hours ago
$begingroup$
Do you measure how hard it is to lift the weight or to keep it in a high position, or both?
$endgroup$
– Arnaud Mortier
2 hours ago
$begingroup$
@noedne Ten people can lift a small car, one person cannot.
$endgroup$
– Arnaud Mortier
2 hours ago
$begingroup$
@noedne Given the final contraption, it's expected to behave as the story.
$endgroup$
– athin
2 hours ago
1
$begingroup$
@ArnaudMortier The measurement can be exact. Say, you need $x$ Newton to perform those $3$ pullings. (Well, for the third one, it should be $2x$ Newton in total as using both of hands $= x + x$.)
$endgroup$
– athin
2 hours ago
$begingroup$
Is this unexpected?
$endgroup$
– noedne
2 hours ago
$begingroup$
Is this unexpected?
$endgroup$
– noedne
2 hours ago
$begingroup$
Do you measure how hard it is to lift the weight or to keep it in a high position, or both?
$endgroup$
– Arnaud Mortier
2 hours ago
$begingroup$
Do you measure how hard it is to lift the weight or to keep it in a high position, or both?
$endgroup$
– Arnaud Mortier
2 hours ago
$begingroup$
@noedne Ten people can lift a small car, one person cannot.
$endgroup$
– Arnaud Mortier
2 hours ago
$begingroup$
@noedne Ten people can lift a small car, one person cannot.
$endgroup$
– Arnaud Mortier
2 hours ago
$begingroup$
@noedne Given the final contraption, it's expected to behave as the story.
$endgroup$
– athin
2 hours ago
$begingroup$
@noedne Given the final contraption, it's expected to behave as the story.
$endgroup$
– athin
2 hours ago
1
1
$begingroup$
@ArnaudMortier The measurement can be exact. Say, you need $x$ Newton to perform those $3$ pullings. (Well, for the third one, it should be $2x$ Newton in total as using both of hands $= x + x$.)
$endgroup$
– athin
2 hours ago
$begingroup$
@ArnaudMortier The measurement can be exact. Say, you need $x$ Newton to perform those $3$ pullings. (Well, for the third one, it should be $2x$ Newton in total as using both of hands $= x + x$.)
$endgroup$
– athin
2 hours ago
add a comment |
4 Answers
4
active
oldest
votes
$begingroup$
Possible answer
The ropes themselves are significantly heavier than the single weight so that when you lift with either with the left or right hand you're mostly lifting the rope on that side (together with small contributions from the weight and the end of the other rope). When you lift with both hands, you are lifting both ropes.
answered 1 hour ago
hexominohexomino
47.8k4143225
$endgroup$
add a comment |
$begingroup$
Maybe the ropes are
attached to different ends of the thin weight, which is lying flat inside the box.
When you pull only one rope,
only that end of the weight rises. The centre of mass of the weight moves up by half the distance pulled, so the force required is half of the weight of the weight
And when you pull on both ropes
The whole weight rises, and the force is equally split between the two ropes.
In both cases, the force on any pulled rope is the same, namely
one half of the weight of the weight.
answered 1 hour ago
BassBass
31.6k475194
$endgroup$
$begingroup$
My physics is rusty, but I don't think the distance moved affects the forces.
$endgroup$
– noedne
1 hour ago
$begingroup$
@noedne Sure it does. It all comes back to the law of the lever: gravity pulls down at the center of mass, and the rope pulls up at exactly twice the distance from the fulcrum, which we know from the fact that the rope moves twice as much as the center of gravity.
$endgroup$
– Bass
1 hour ago
$begingroup$
Thanks, I see it now.
$endgroup$
– noedne
1 hour ago
add a comment |
$begingroup$
The weight is attached to a pulley. The two ends are of the same rope that runs through the pulley. Also, the rope is tied to two ropes that connect it to the top of the box on either side of the pulley. When you pull one end of the rope, the pulley lets you cut the weight in half, but when you pull on both ends, you do not use the pulley and lift the entire weight.
Below is my attempt at depicting this contraption.
answered 1 hour ago
noednenoedne
9,76812668
$endgroup$
$begingroup$
My physics is quite rusty, so please let me know if this is mistaken.
$endgroup$
– noedne
1 hour ago
5
$begingroup$
All hail the mighty man in the box, balancing a table on his long arms!
$endgroup$
– infinitezero
1 hour ago
add a comment |
$begingroup$
This explains it:
The box is sealed from outside and the ropes are not connected to the weight. When you pull the ropes out you are creating a pressure difference caused by the displacement of the volume occupied by the ropes (isochoric process). If the ropes are equal in size, this will mean that by he same displacement per rope, i.e. the same pressure difference per rope thus the same force per rope.
This is analogous to a case where you connect two syringes (instead of ropes) to a sealed box (optionally with something just laying inside it).
answered 1 hour ago
cinicocinico
1565
$endgroup$
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Possible answer
The ropes themselves are significantly heavier than the single weight so that when you lift with either with the left or right hand you're mostly lifting the rope on that side (together with small contributions from the weight and the end of the other rope). When you lift with both hands, you are lifting both ropes.
answered 1 hour ago
hexominohexomino
47.8k4143225
$endgroup$
add a comment |
$begingroup$
Possible answer
The ropes themselves are significantly heavier than the single weight so that when you lift with either with the left or right hand you're mostly lifting the rope on that side (together with small contributions from the weight and the end of the other rope). When you lift with both hands, you are lifting both ropes.
answered 1 hour ago
hexominohexomino
47.8k4143225
$endgroup$
add a comment |
$begingroup$
Possible answer
The ropes themselves are significantly heavier than the single weight so that when you lift with either with the left or right hand you're mostly lifting the rope on that side (together with small contributions from the weight and the end of the other rope). When you lift with both hands, you are lifting both ropes.
answered 1 hour ago
hexominohexomino
47.8k4143225
$endgroup$
Possible answer
The ropes themselves are significantly heavier than the single weight so that when you lift with either with the left or right hand you're mostly lifting the rope on that side (together with small contributions from the weight and the end of the other rope). When you lift with both hands, you are lifting both ropes.
answered 1 hour ago
hexominohexomino
47.8k4143225
answered 1 hour ago
hexominohexomino
47.8k4143225
answered 1 hour ago
hexominohexomino
47.8k4143225
answered 1 hour ago
hexominohexomino
47.8k4143225
47.8k4143225
add a comment |
add a comment |
$begingroup$
Maybe the ropes are
attached to different ends of the thin weight, which is lying flat inside the box.
When you pull only one rope,
only that end of the weight rises. The centre of mass of the weight moves up by half the distance pulled, so the force required is half of the weight of the weight
And when you pull on both ropes
The whole weight rises, and the force is equally split between the two ropes.
In both cases, the force on any pulled rope is the same, namely
one half of the weight of the weight.
answered 1 hour ago
BassBass
31.6k475194
$endgroup$
$begingroup$
My physics is rusty, but I don't think the distance moved affects the forces.
$endgroup$
– noedne
1 hour ago
$begingroup$
@noedne Sure it does. It all comes back to the law of the lever: gravity pulls down at the center of mass, and the rope pulls up at exactly twice the distance from the fulcrum, which we know from the fact that the rope moves twice as much as the center of gravity.
$endgroup$
– Bass
1 hour ago
$begingroup$
Thanks, I see it now.
$endgroup$
– noedne
1 hour ago
add a comment |
$begingroup$
Maybe the ropes are
attached to different ends of the thin weight, which is lying flat inside the box.
When you pull only one rope,
only that end of the weight rises. The centre of mass of the weight moves up by half the distance pulled, so the force required is half of the weight of the weight
And when you pull on both ropes
The whole weight rises, and the force is equally split between the two ropes.
In both cases, the force on any pulled rope is the same, namely
one half of the weight of the weight.
answered 1 hour ago
BassBass
31.6k475194
$endgroup$
$begingroup$
My physics is rusty, but I don't think the distance moved affects the forces.
$endgroup$
– noedne
1 hour ago
$begingroup$
@noedne Sure it does. It all comes back to the law of the lever: gravity pulls down at the center of mass, and the rope pulls up at exactly twice the distance from the fulcrum, which we know from the fact that the rope moves twice as much as the center of gravity.
$endgroup$
– Bass
1 hour ago
$begingroup$
Thanks, I see it now.
$endgroup$
– noedne
1 hour ago
add a comment |
$begingroup$
Maybe the ropes are
attached to different ends of the thin weight, which is lying flat inside the box.
When you pull only one rope,
only that end of the weight rises. The centre of mass of the weight moves up by half the distance pulled, so the force required is half of the weight of the weight
And when you pull on both ropes
The whole weight rises, and the force is equally split between the two ropes.
In both cases, the force on any pulled rope is the same, namely
one half of the weight of the weight.
answered 1 hour ago
BassBass
31.6k475194
$endgroup$
Maybe the ropes are
attached to different ends of the thin weight, which is lying flat inside the box.
When you pull only one rope,
only that end of the weight rises. The centre of mass of the weight moves up by half the distance pulled, so the force required is half of the weight of the weight
And when you pull on both ropes
The whole weight rises, and the force is equally split between the two ropes.
In both cases, the force on any pulled rope is the same, namely
one half of the weight of the weight.
answered 1 hour ago
BassBass
31.6k475194
edited 1 hour ago
answered 1 hour ago
BassBass
31.6k475194
answered 1 hour ago
BassBass
31.6k475194
answered 1 hour ago
BassBass
31.6k475194
31.6k475194
$begingroup$
My physics is rusty, but I don't think the distance moved affects the forces.
$endgroup$
– noedne
1 hour ago
$begingroup$
@noedne Sure it does. It all comes back to the law of the lever: gravity pulls down at the center of mass, and the rope pulls up at exactly twice the distance from the fulcrum, which we know from the fact that the rope moves twice as much as the center of gravity.
$endgroup$
– Bass
1 hour ago
$begingroup$
Thanks, I see it now.
$endgroup$
– noedne
1 hour ago
add a comment |
$begingroup$
My physics is rusty, but I don't think the distance moved affects the forces.
$endgroup$
– noedne
1 hour ago
$begingroup$
@noedne Sure it does. It all comes back to the law of the lever: gravity pulls down at the center of mass, and the rope pulls up at exactly twice the distance from the fulcrum, which we know from the fact that the rope moves twice as much as the center of gravity.
$endgroup$
– Bass
1 hour ago
$begingroup$
Thanks, I see it now.
$endgroup$
– noedne
1 hour ago
$begingroup$
My physics is rusty, but I don't think the distance moved affects the forces.
$endgroup$
– noedne
1 hour ago
$begingroup$
My physics is rusty, but I don't think the distance moved affects the forces.
$endgroup$
– noedne
1 hour ago
$begingroup$
@noedne Sure it does. It all comes back to the law of the lever: gravity pulls down at the center of mass, and the rope pulls up at exactly twice the distance from the fulcrum, which we know from the fact that the rope moves twice as much as the center of gravity.
$endgroup$
– Bass
1 hour ago
$begingroup$
@noedne Sure it does. It all comes back to the law of the lever: gravity pulls down at the center of mass, and the rope pulls up at exactly twice the distance from the fulcrum, which we know from the fact that the rope moves twice as much as the center of gravity.
$endgroup$
– Bass
1 hour ago
$begingroup$
Thanks, I see it now.
$endgroup$
– noedne
1 hour ago
$begingroup$
Thanks, I see it now.
$endgroup$
– noedne
1 hour ago
add a comment |
$begingroup$
The weight is attached to a pulley. The two ends are of the same rope that runs through the pulley. Also, the rope is tied to two ropes that connect it to the top of the box on either side of the pulley. When you pull one end of the rope, the pulley lets you cut the weight in half, but when you pull on both ends, you do not use the pulley and lift the entire weight.
Below is my attempt at depicting this contraption.
answered 1 hour ago
noednenoedne
9,76812668
$endgroup$
$begingroup$
My physics is quite rusty, so please let me know if this is mistaken.
$endgroup$
– noedne
1 hour ago
5
$begingroup$
All hail the mighty man in the box, balancing a table on his long arms!
$endgroup$
– infinitezero
1 hour ago
add a comment |
$begingroup$
The weight is attached to a pulley. The two ends are of the same rope that runs through the pulley. Also, the rope is tied to two ropes that connect it to the top of the box on either side of the pulley. When you pull one end of the rope, the pulley lets you cut the weight in half, but when you pull on both ends, you do not use the pulley and lift the entire weight.
Below is my attempt at depicting this contraption.
answered 1 hour ago
noednenoedne
9,76812668
$endgroup$
$begingroup$
My physics is quite rusty, so please let me know if this is mistaken.
$endgroup$
– noedne
1 hour ago
5
$begingroup$
All hail the mighty man in the box, balancing a table on his long arms!
$endgroup$
– infinitezero
1 hour ago
add a comment |
$begingroup$
The weight is attached to a pulley. The two ends are of the same rope that runs through the pulley. Also, the rope is tied to two ropes that connect it to the top of the box on either side of the pulley. When you pull one end of the rope, the pulley lets you cut the weight in half, but when you pull on both ends, you do not use the pulley and lift the entire weight.
Below is my attempt at depicting this contraption.
answered 1 hour ago
noednenoedne
9,76812668
$endgroup$
The weight is attached to a pulley. The two ends are of the same rope that runs through the pulley. Also, the rope is tied to two ropes that connect it to the top of the box on either side of the pulley. When you pull one end of the rope, the pulley lets you cut the weight in half, but when you pull on both ends, you do not use the pulley and lift the entire weight.
Below is my attempt at depicting this contraption.
answered 1 hour ago
noednenoedne
9,76812668
edited 1 hour ago
answered 1 hour ago
noednenoedne
9,76812668
answered 1 hour ago
noednenoedne
9,76812668
answered 1 hour ago
noednenoedne
9,76812668
9,76812668
$begingroup$
My physics is quite rusty, so please let me know if this is mistaken.
$endgroup$
– noedne
1 hour ago
5
$begingroup$
All hail the mighty man in the box, balancing a table on his long arms!
$endgroup$
– infinitezero
1 hour ago
add a comment |
$begingroup$
My physics is quite rusty, so please let me know if this is mistaken.
$endgroup$
– noedne
1 hour ago
5
$begingroup$
All hail the mighty man in the box, balancing a table on his long arms!
$endgroup$
– infinitezero
1 hour ago
$begingroup$
My physics is quite rusty, so please let me know if this is mistaken.
$endgroup$
– noedne
1 hour ago
$begingroup$
My physics is quite rusty, so please let me know if this is mistaken.
$endgroup$
– noedne
1 hour ago
5
5
$begingroup$
All hail the mighty man in the box, balancing a table on his long arms!
$endgroup$
– infinitezero
1 hour ago
$begingroup$
All hail the mighty man in the box, balancing a table on his long arms!
$endgroup$
– infinitezero
1 hour ago
add a comment |
$begingroup$
This explains it:
The box is sealed from outside and the ropes are not connected to the weight. When you pull the ropes out you are creating a pressure difference caused by the displacement of the volume occupied by the ropes (isochoric process). If the ropes are equal in size, this will mean that by he same displacement per rope, i.e. the same pressure difference per rope thus the same force per rope.
This is analogous to a case where you connect two syringes (instead of ropes) to a sealed box (optionally with something just laying inside it).
answered 1 hour ago
cinicocinico
1565
$endgroup$
add a comment |
$begingroup$
This explains it:
The box is sealed from outside and the ropes are not connected to the weight. When you pull the ropes out you are creating a pressure difference caused by the displacement of the volume occupied by the ropes (isochoric process). If the ropes are equal in size, this will mean that by he same displacement per rope, i.e. the same pressure difference per rope thus the same force per rope.
This is analogous to a case where you connect two syringes (instead of ropes) to a sealed box (optionally with something just laying inside it).
answered 1 hour ago
cinicocinico
1565
$endgroup$
add a comment |
$begingroup$
This explains it:
The box is sealed from outside and the ropes are not connected to the weight. When you pull the ropes out you are creating a pressure difference caused by the displacement of the volume occupied by the ropes (isochoric process). If the ropes are equal in size, this will mean that by he same displacement per rope, i.e. the same pressure difference per rope thus the same force per rope.
This is analogous to a case where you connect two syringes (instead of ropes) to a sealed box (optionally with something just laying inside it).
answered 1 hour ago
cinicocinico
1565
$endgroup$
This explains it:
The box is sealed from outside and the ropes are not connected to the weight. When you pull the ropes out you are creating a pressure difference caused by the displacement of the volume occupied by the ropes (isochoric process). If the ropes are equal in size, this will mean that by he same displacement per rope, i.e. the same pressure difference per rope thus the same force per rope.
This is analogous to a case where you connect two syringes (instead of ropes) to a sealed box (optionally with something just laying inside it).
answered 1 hour ago
cinicocinico
1565
edited 56 mins ago
answered 1 hour ago
cinicocinico
1565
answered 1 hour ago
cinicocinico
1565
answered 1 hour ago
cinicocinico
1565
1565
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$begingroup$
Is this unexpected?
$endgroup$
– noedne
2 hours ago
$begingroup$
Do you measure how hard it is to lift the weight or to keep it in a high position, or both?
$endgroup$
– Arnaud Mortier
2 hours ago
$begingroup$
@noedne Ten people can lift a small car, one person cannot.
$endgroup$
– Arnaud Mortier
2 hours ago
$begingroup$
@noedne Given the final contraption, it's expected to behave as the story.
$endgroup$
– athin
2 hours ago
1
$begingroup$
@ArnaudMortier The measurement can be exact. Say, you need $x$ Newton to perform those $3$ pullings. (Well, for the third one, it should be $2x$ Newton in total as using both of hands $= x + x$.)
$endgroup$
– athin
2 hours ago